3 years ago

EXPERIMENT 1: Identify the oxidation and reduction half-reactions that occur in

Chemistry

1 answer:

Hoochie [10]3 years ago

4 0

Answer:

Cathode: Mn → Mn²⁺ + 2e⁻ (Oxidation)

Anode: Zn²⁺ + 2e⁻ → Zn (Reduction)

Mn | Mn²⁺ || Zn²⁺ | Zn

Explanation:

To identify the half reaction we need to see the oxidation states.

Mn(s) → Ground state → Oxidation state = 0

Mn(NO₃)₂ → Mn²⁺ → The oxidation state has increased.

This is the oxidation reaction. It has released two electrons:

Mn → Mn²⁺ + 2e⁻

Zn(NO₃)₂ → Zn²⁺

Zn → Ground state → The oxidation state was decreased.

This is the reduction reaction. It has gained two electrons:

Zn²⁺ + 2e⁻ → Zn

Cathode: Mn → Mn²⁺ + 2e⁻

Anode: Zn²⁺ + 2e⁻ → Zn

Mn | Mn²⁺ || Zn²⁺ | Zn

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