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Vikki [24]
3 years ago
12

EXPERIMENT 1: Identify the oxidation and reduction half-reactions that occur in

Chemistry
1 answer:
Hoochie [10]3 years ago
4 0

Answer:

Cathode: Mn → Mn²⁺  +  2e⁻    (Oxidation)

Anode: Zn²⁺  +  2e⁻  →  Zn   (Reduction)

Mn | Mn²⁺ ||  Zn²⁺  | Zn

Explanation:

To identify the half reaction we need to see the oxidation states.

Mn(s) → Ground state → Oxidation state = 0

Mn(NO₃)₂ → Mn²⁺  → The oxidation state has increased.

This is the oxidation reaction. It has released two electrons:

Mn → Mn²⁺  +  2e⁻

Zn(NO₃)₂ →  Zn²⁺

Zn → Ground state → The oxidation state was decreased.

This is the reduction reaction. It has gained two electrons:

Zn²⁺  +  2e⁻  →  Zn

Cathode: Mn → Mn²⁺  +  2e⁻

Anode: Zn²⁺  +  2e⁻  →  Zn

Mn | Mn²⁺ ||  Zn²⁺  | Zn

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Which statement correctly explains how magnesium and chlorine combine to form magnesium chloride?
AysviL [449]
You did not include the statements but since magnesium chloride is ionic substance that we know that magnesium and chlorine formed an ionic bond.  Therefore your statement most likely will talk about how one magnesium atom gave up 2 electrons while two chlorine atoms took 1 electron.  The reaction looks like Mg+2Cl⇒MgCl₂.  
I hope this helps.  Let me know in the comments if anything is unclear.
4 0
3 years ago
Read 2 more answers
HIII PLEASE HELP BRUUH
leonid [27]

1. 2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)

2. 2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)

3. 2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)

<h3>Further explanation</h3>

There are several reactions that can occur in a chemical reaction: single replacement, double replacement, synthesis, decomposition or combustion, etc.

1.Al(s)+HCl(aq)⇒AlCl₃(aq)+H₂(g)

type : single replacement

balance :

2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)

2. AgNO₃ (aq) + Cu (s) ⇒ Cu(NO₃)₂ (aq) + Ag (s)

type : single replacement

balance :

2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)

3. C₃H₈O + O₂ ⇒ CO₂ + H₂O

type : combustion of alcohol

balance :

2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)

4 0
3 years ago
A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydro
lutik1710 [3]
  • The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.
  • That is approximately 0.001758.
  • Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas.
  • The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter.
<h3>Is it true that calculations made utilizing experimental and gathered data result in a percent error? </h3>
  • Consequently, we are aware that magnesium and chloride react.
  • We create 1 as the reaction ratio is 1:2.
  • The hydrogen and 1 are more.
  • Magnesium chloride is more.
  • Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more.
  • Among hydrogen, there is.
  • \Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin.
  • The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter.
  • Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.
  • So, in this instance, we are aware that p v = n r t.
  • The r in this case equals p v over n t, thus we want to determine the r.
  • So p is 110922.24. The temperature is 305.15 and the V is 0.04  over the n is 0.001758.
  • Let's proceed with the calculations right now.
  • In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

To learn more about Magnesium chloride reactions visit:

brainly.com/question/27891157

#SPJ4

3 0
2 years ago
What is the difference between a physical change and a chemical change? (2 points)
charle [14.2K]

A physical change does not change the identity of the substance but the chemical change does.


Example

If you tear or shred a piece of paper it is still paper, but if you pour chemicals on it it will probably change to something else.

7 0
3 years ago
Read 2 more answers
Question 6 1.75 pts The following reaction 2H2S(g)=2H2(g)+S2(g), Kc=1.625x10-7 at 800°C is carried out at the same temperature w
kirza4 [7]

Answer:

[S₂] = 1.27×10⁻⁷ M

Explanation:

2 H₂S(g) ⇄ 2 H₂(g) + S₂(g), Kc=1,625x10⁻⁷

The equation of this reaction is:

1,625x10⁻⁷ = \frac{[H_2]^2[S_2]}{[H_{2}S]^2}

The equilibrium concentrations are:

[H₂S] = 0,162 - 2x

[H₂] = 0,184 + 2x

[S₂] = x

Replacing:

1,625x10⁻⁷ = \frac{[0,184+2x]^2[x]}{[0,162-2x]^2}

Solving:

4x³ + 0,736x² + 0,033856x - 4,3x10⁻⁹

x = 1.27×10⁻⁷

Thus, concentration of S₂ is:

<em>[S₂] = 1.27×10⁻⁷ M</em>

4 0
3 years ago
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