Answer: There are
five <span>bonding pairs of electrons in Methanol.
Explanation: Those electron pairs which are being shared between two atoms in molecule are called as
bonding pair electrons. While, those electron pairs which are not involved in bond formation and are not shared between two atoms are called as
Non-Bonding electron pairs.
In molecule of
Methanol as shown below, it can be seen that carbon atom is forming four bonds with three hydrogen atoms and one oxygen atom by sharing four electron pairs and oxygen is forming two bonds, one with carbon atom and one with hydrogen atom. There are two lone pair of electrons present on oxygen atom which are not taking part in and formation.</span>
The given chemical reaction is:

The standard heats of formation of
are:
Δ
) = -285.8kJ/mol[/tex]
Δ
) = -187.6 kJ/mol[/tex]
Calculating the change in heat:
Δ
=∑ΔH
-∑ΔH
= [{2 * (-285.8 kJ/mol)} -{2*(-187.6 kJ/mol)}]
= -196.4 kJ/mol
Therefore, the change in enthalpy for the given reaction is -196.4 kJ/mol
D)100%
Every single one has the dominate gene so all the offspring will get it
I hope that helps!
Answer: 1/12
1/4 divided by 3/1
KCF:Keep the first fraction, Change the sign to muplication, Flip the second fraction.
1/4* 31
1*1=1
4*3=12
1/12
.5/.5 = 1 M, as there would be 1 mol in a liter.