Question

For the balanced equation shown below, how many moles of O2 will react with 0.3020 moles of CO2?

Answer 1

Answer : The number of moles of $O_2$ react will be, 0.453 moles

Solution : Given,

Moles of $CO_2$ = 0.3020 moles

The balanced chemical reaction is,

$2C_2H_5OH+6O_2\rightarrow 4CO_2+6H_2O$

From the balanced reaction, we conclude that

As, 4 moles of $CO_2$ produces form 6 moles of $O_2$

So, 0.3020 moles of $CO_2$ produces from $\frac{6}{4}\times 0.3020=0.453moles$ of $O_2$

Therefore, the number of moles of $O_2$ react will be, 0.453 moles

Answer 2

Answer is: 0,453  moles of oxygen will react with 0.3020 moles of carbon(IV) oxide.
n(CO₂) = 0,302 mol.
From chemical reaction: n(CO₂) : n(O₂) = 4 : 6.
n(O₂) = 6 · 0,302 mol ÷ 4.
n(O₂) = 0,453 mol.
n - amount of substance.