All categories

3 years ago

For the balanced equation shown below, how many moles of O2 will react with 0.3020 moles of CO2?

Chemistry

2 answers:

Vitek1552 [10]3 years ago

7 0

Answer : The number of moles of $O_2$ react will be, 0.453 moles

Solution : Given,

Moles of $CO_2$ = 0.3020 moles

The balanced chemical reaction is,

$2C_2H_5OH+6O_2\rightarrow 4CO_2+6H_2O$

From the balanced reaction, we conclude that

As, 4 moles of $CO_2$ produces form 6 moles of $O_2$

So, 0.3020 moles of $CO_2$ produces from $\frac{6}{4}\times 0.3020=0.453moles$ of $O_2$

Therefore, the number of moles of $O_2$ react will be, 0.453 moles

andrezito [222]3 years ago

6 0

Answer is: 0,453 <span> moles of oxygen will react </span><span>with 0.3020 moles of carbon(IV) oxide</span><span>.
</span>n(CO₂) = 0,302 mol.
From chemical reaction: n(CO₂) : n(O₂) = 4 : 6.
n(O₂) = 6 · 0,302 mol ÷ 4.
n(O₂) = 0,453 mol.
n - amount of substance.

You might be interested in

The initial activity of 37Ar is 8540 disintegrations per minute. After 10.0 days, the activity is 6990 disintegrations per minut

mylen [45]

Answer:

Approximately 3318 disintegrations per minute.

Explanation:

The activity $A$ of a radioactive decay at time $t$ can be found with the following equation:

$\displaystyle A(t) = A_0 \cdot \mathrm{e}^{-\lambda\cdot t}$ .

In this equation,

$\mathrm{e}$ is the natural base. $\mathrm{e}\approx 2.71828$ .
$A_0$ is the initial activity of the decay. For this question, $A_0 = \rm 8540\; min^{-1}$ .
The decay constant $\lambda$ of this sample needs to be found.

The decay constant here can be found using the activity after 10 days. As long as both times are in the same unit (days in this case,) conversion will not be necessary.

$A(10) = A_0\cdot \mathrm{e}^{\rm -\lambda \times 10\;day}= (\mathrm{8540\; min^{-1}})\cdot \mathrm{e}^{\rm -\lambda \times 10\;day}$ .

$A(10) = \rm 6690\; min^{-1}$ .

$\displaystyle \frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}} = \mathrm{e}^{\rm -\lambda \times 10\;day}$

Apply the natural logarithm to both sides of this equation.

$\displaystyle \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)} = \ln{\left(\mathrm{e}^{\rm -\lambda \times 10\;day}\right)}$ .

$\displaystyle \rm -\lambda \cdot (10\;day) = \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)}$ .

$\displaystyle \rm \lambda= \rm \frac{\displaystyle \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)}}{-10 \; day} \approx 0.0200280\; day^{-1}$ .

Note that the unit of the decay constant $\lambda$ is $\rm day^{-1}$ (the reciprocal of days.) The exponent $-\lambda \cdot t$ should be dimensionless. In other words, the unit of $t$ should also be days. This observation confirms that there's no need for unit conversion as long as the two times are in the same unit.

Apply the equation for decay activity at time $t$ to find the decay activity after 47.2 days.

$\displaystyle \begin{aligned}A(t)& = A_0 \cdot \mathrm{e}^{-\lambda\cdot t}\\&\approx \rm \left(8540\; min^{-1}\right)\cdot \mathrm{e}^{-0.0200280\; day^{-1}\times 47.2\;day}\\&\approx \rm 3318\; min^{-1}\end{aligned}$ .

By dimensional analysis, the unit of activity here should also be disintegrations per minute. The activity after 47.2 days will be approximately 3318 disintegrations per minute.

8 0

2 years ago

What element can scratch a diomand?

borishaifa [10]

Answer:

another diamond ....theres nothing else that can that I know of.

3 0

2 years ago

If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).

11111nata11111 [884]

Answer:

${ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 = \frac{11}{m _{r}} \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\ \\ { \bf{vapour \: density = 2 \times m _{r}}} \\ = 2 \times 14.85 \\ = 29.7 \: { \tt{g {dm}^{ - 3} }}$

7 0

2 years ago

Is the dissolution of borax in water a temperature dependent reaction or is it spontaneous at all temperatures at which water is

enot [183]

The dissolution of borax in water is a temperature dependent reaction. With the higher temperature, the salt dissolve quickly.

<h3>What is borax?</h3>

Borax is the hydrate salt of boric acid. It is white and widely used in cleaning and in laundry detergent.

Borax is a salt that will dissolve in water at almost any temperature, with the exception of steam and ice.

However, as with any salt, the higher the temperature, the faster the salt dissolves, so speed is dependent on temperature. It will dissolve in cold water, but it will take longer.

Thus, the dissolution of borax in water is a temperature dependent reaction.

Learn more about borax

brainly.com/question/14724418

#SPJ4

8 0

1 year ago

What is the highest point of the wave a transverse wave called

topjm [15]

<span>The answer to the question "what is the highest point of the transverse wave called" is a crest or peak. A transverse wave is a wave in which the medium of the wave vibrates at 90 degrees to the direction in which the wave is moving at. The lowest points are called the troughs. Examples of transverse waves are light and electromagnetic radiation.</span>

7 0

2 years ago

Read 2 more answers