Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
![\frac{5}{100}x+\frac{6}{100}(6000-x)=337.5](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B100%7Dx%2B%5Cfrac%7B6%7D%7B100%7D%286000-x%29%3D337.5%20%20%20)
Multiplying both sides by 100 we get:
![5x+6(6000-x)=33750](https://tex.z-dn.net/?f=%205x%2B6%286000-x%29%3D33750%20)
![5x+36000-6x=33750](https://tex.z-dn.net/?f=%205x%2B36000-6x%3D33750%20)
Subtracting both sides by 36000 we get:
![-x=-2250](https://tex.z-dn.net/?f=%20-x%3D-2250%20)
![\therefore x=2250](https://tex.z-dn.net/?f=%20%5Ctherefore%20x%3D2250%20)
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
<span>Y DO I W? (Why do I double you?)
That's the answer. </span>
Answer:
![\frac{9}{47}: 1](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B47%7D%3A%201)
Step-by-step explanation:
you can divide both sides by 2.35 to get the right side to be 1:
![4.5: 2.35\\\frac{9}{47}: 1](https://tex.z-dn.net/?f=4.5%3A%202.35%5C%5C%5Cfrac%7B9%7D%7B47%7D%3A%201)
Answer:
the answer is the last one, you solve this by comparing the lines from each shape. these shapes are congruent, meaning they're the same, so the like AB on the first shape and EF on the second are the same, and so on if that makes any sense. surely someone else could do a better explanation than me tho
Part 1: 2×2×3×3×3=108 (c)
Part 2: 10×9×26×25×4=234000 (c)
Part 3: 10×9×8×7×6×5×4×3×2×1÷(3×2×1)=604800 (d)
Part 4: 11C4=11×10×9×8÷(4×3×2×1)=330 (a)
Part 5: ⅕=20% (c)
Part 6: 100-2.9=97.1 (d)