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Lubov Fominskaja [6]
2 years ago
10

Which best describes a rectangle with diagonals that are perpendicular?

Mathematics
1 answer:
solong [7]2 years ago
8 0

Answer:

Rhombus

Step-by-step explanation:

If a parallelogram has diagonals that are perpendicular, it is a rhombus. A square is a parallelogram with four congruent sides and four right angles. This definition can also be stated as: A square is a quadrilateral that is also a rectangle and a rhombus.

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Dan and Jake have new stamp collecting books. Dan puts 5 stamps in his book every day, and Jake puts 6 stamps in his book every
Ghella [55]
Jake puts 6 stamps in his book every day.

30/6= 5 

Jake put stamps in the book for 5 days.

So, Dan puts 5 stamps in the book every day.

5*5= 25

Dan has 25 stamps when Jake has 30.

I hope this helps!
~kaikers


4 0
3 years ago
.Bryan was given the equation y= -5x+3. He says the rate of change is 3 and the initial value is -5. Is Bryan correct? If not, c
Mekhanik [1.2K]

Answer:

Correct rate of change is -5; correct initial value is 3.

Step-by-step explanation:

The rate of change is the coefficient of the x term, which here is -5.  So Bryan has the rate of change wrong.

The initial value of the function is found by letting x  =  0.  Here, we get

y = -5(0) + 3, or y = b = 3.  The initial value is 3, not -5.

8 0
2 years ago
Which of the relations given by the following sets of ordered pairs is a function?
KonstantinChe [14]

9514 1404 393

Answer:

  (a)  {(5, 2), (-4, 2), (3, 6), (0, 4), (-1, 2)}

Step-by-step explanation:

The only relation with no repeated x-values is the first one. The first relation is a function.

6 0
3 years ago
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
3 0
3 years ago
Plz help :) will mark brainliest if correct
Vedmedyk [2.9K]

Answer:

1st

Step-by-step explanation:

7 0
2 years ago
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