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fiasKO [112]
3 years ago
5

The range of y = - 32x ^ 2 + 90x + 3

Mathematics
2 answers:
Digiron [165]3 years ago
7 0

Answer:

y ≤ 66.28 -> -∞

Step-by-step explanation:

y = a (x-h)² + k     ... (h,k): vertex

y = - 32x² + 90x + 3

  = -32 (x² - (90/32)x + (90/64)²) + (3 + (32)*(90/64)²)

  = -32 (x² - 2*(90/64)x + (90/64)²) + (3+63.28)   ... 90/64=1.41

  = -32 (x - 1.41)² + 66.28

h = 1.41

k = 66.28 .... extremum of y value

y ≤ 66.28 (y is real number)

motikmotik3 years ago
5 0

Enter a problem...

Algebra Examples

Popular Problems Algebra Find the Domain and Range y=3/2x^2+4x-9

y

=

3

2

x

2

+

4

x

−

9

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

x

|

x

∈

R

}

The range is the set of all valid

y

values. Use the graph to find the range.

Interval Notation:

[

−

35

3

,

∞

)

Set-Builder Notation:

{

y

∣

∣

∣

y

≥

−

35

3

}

Determine the domain and range.

Domain:

(

−

∞

,

∞

)

,

{

x

|

x

∈

R

}

Range:

[

−

35

3

,

∞

)

,

{

y

∣

∣

∣

y

≥

−

35

3

}

image of graph

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<4 = 180-29

<4 = 151°

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