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2 years ago

What is the other name for continuous variables?

Mathematics

1 answer:

astraxan [27]2 years ago

8 0

Answer:

Nominal variables.

Step-by-step explanation:

In Mathematics, a random variable can be defined as any variable whose values are determined by the outcome of a random experiment.

Basically, random variables are classified into two (2) main categories and these are;

1. Discrete variable: a discrete variable is a data set in which the number of possible values are either finite or countable. For instance, the value of a fair die, number of sweets in a jar, number of eggs in a crate etc.

2. Continuous variable: a continuous variable is a data set having infinitely many possible values and those values cannot be counted, meaning they are uncountable. Any quantity such as height, volume, weight, density, length, pressure, temperature, speed, distance, time are generally a continuous random variable.

Hence, the other name for continuous variables is nominal variables because they are numerical in nature.

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jek_recluse [69]

First, we can convert both of them to improper fractions.

We do that by multiplying the denominator to the whole number, adding it to the numerator, and keeping the denominator.

2 5/3 - 2 3/2

So we have:

11/3 - 7/2

Convert both of them to denominators of 6:

22/6 - 21/6

Subtract the numerators and keep the denominators:

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3 years ago

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For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog

natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

$cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}$

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

$cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}$

$\angle GAB = cos^{-1} \left (\dfrac{36}{39} \right )$

∠GAB = 22.62°

$cos(\angle GAB) = \dfrac{36}{39} = \dfrac{12}{GH}$

$GH = \dfrac{39}{36} \times {12}$

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) = 13 × sin(45.24°)

The height of the parallelogram = 120/13 = 9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

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3 years ago

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A school is holding a talent show. A group of six friends entered the talent show and won the first place prize of $45, which th

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Answer:

<em>In the second group the individual members received a larger fraction of the prize money</em>

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<u>Division by Sharing</u>

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The first group of six friends earned $45 and they split it evenly, i.e. the same amount goes to each member. Each of them received $45/6= $7.50 apiece.

The second group of four friends won the second-place prize of $35 and they split it evenly also. Each member received $35/4=$8.75.

By comparing both numbers, we see that 8.75 is a bigger fraction of 35 that 7.50 is of 45. Each member from the second-place price will receive more money than the first group.

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PLEASE HELP!!

SIZIF [17.4K]

(x, y)

Domain = x

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Mkey [24]

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