All categories

3 years ago

PLEASE HELP!!

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

(x, y)

Domain = x

Range = y

It is a function when none of the x values are repeating.

Answer - C) Both A and B

Hope this helps and makes sense!!

You might be interested in

Which of these government programs encourage hygiene practices

Paha777 [63]

Government programs help to protect citizens from possible hazards

exposure.

The government program that encourage hygiene practices is A.

Transportation regulations to prevent overcrowding.

Reasons:

Hygiene practices which include mainly cleanliness measures, meant to

keep a person healthy as well as to prevent contraction of disease.

Government programs such as stipulating social distancing rules reduces

airborne diseases, and other contagious diseases, and such programs are

useful as part of transport regulations.

Therefore, the government program that encourage hygiene practice

transport regulations to prevent overcrowding.

Learn more here:

brainly.com/question/10560365

6 0

3 years ago

I found the interval of convergence, but I am not sure how to do the second part, finding the sum of the series as a function of

antiseptic1488 [7]

The given series is geometric with common ratio $6^x - 9$ , which converges if $|6^x - 9|$ (i.e. the interval of convergence). We have the well-known result

$\displaystyle |r| < 1 \implies \sum_{n=0}^\infty ar^n = \frac{a}{1-r}$

If you're not familiar with that result, it's easy to reproduce.

Let $S_N$ be the $N$ -th partial sum of the infinite series,

$\displaystyle S_N = \sum_{n=0}^N \left(6^x - 9\right)^n = 1 + \left(6^x - 9\right) + \left(6^x - 9\right)^2 + \cdots + \left(6^x - 9\right)^N$

Multiply both sides by the ratio.

$\left(6^x - 9\right) S_N = \left(6^x - 9\right) + \left(6^x - 9\right)^2 + \left(6^x - 9\right)^3 + \cdots + \left(6^x - 9\right)^{N+1}$

Subtract this from $S_N$ to eliminate all the powers of the ratio between 0 and $N+1$ .

$\left(1 - \left(6^x - 9\right)\right) S_N = 1 - \left(6^x - 9\right)^{N+1}$

Solve for $S_N$ .

$S_N = \dfrac{1 - \left(6^x - 9\right)^{N+1}}{10-6^x}$

Now as $N\to\infty$ , the exponential term converges to 0 and we're left with

$\displaystyle \sum_{n=0}^\infty \left(6^x-9\right)^n = \lim_{N\to\infty} S_N = \boxed{\frac1{10-6^x}}$

7 0

2 years ago

Write an equation of the line that passes through the given points: (9/2,1), (-7/2,7) please show step by step how to do this. T

Viktor [21]

Explanation:

The easiest way to do this is to make use of the 2-point form of the equation for a line. For points (x₁, y₁) and (x₂, y₂), the equation is ...

$y=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)+y_1$

Filling in your given points, the equation becomes ...

$y=\dfrac{7-1}{\frac{-7}{2}-\frac{9}{2}}(x-\frac{9}{2})+1$

After you fill in the values, it is a matter of simplifying the resulting equation.

$y=\dfrac{6}{\frac{-16}{2}}(x-\frac{9}{2})+1=\dfrac{-12}{16}(x-\frac{9}{2})+1=-\dfrac{3}{4}x+\left(\dfrac{-3}{4}\cdot\dfrac{-9}{2}\right)+1\\\\y=-\dfrac{3}{4}x+\dfrac{27+8}{8}\\\\y=-\dfrac{3}{4}x+\dfrac{35}{8}$

6 0

4 years ago

Liz needs to keep no less than $500 in her checking account to avoid fees. she had $524.75 before writing a check for $65.99. ho

____ [38]

If she needs to keep $500 in her account and she just wrote a check for $65.99 she needs to deposit $41.24 to be at $500 when the $65.99 is withdrawn.

8 0

3 years ago

Rewriting expressions using algebraic properties doesn't change the value of the expression or the relationship it describes.

kiruha [24]

Answer:

see attached

Step-by-step explanation:

No doubt you have examples showing the wording that is expected to be used here. We have made a guess.

power of a ratio: the numerator is raised to the power, as is the denominator. (a/b)^c = (a^c)/(b^c)

power of a product: each factor is raised to the power. (ab)^c = (a^c)(b^c)

power of a power: the powers are multiplied. (a^b)^c = a^(bc)

quotient of powers: the result when one power is divided by another is the difference of the numerator and denominator powers. (a^b)/(a^c) = a^(b-c)

_____

Additional comment

The order of operations tells you to simplify inside parentheses first. Doing that reduces the work somewhat.

$\left(\dfrac{-3x^3y}{x^2}\right)^4=(-3xy)^4=(-3)^4x^4y^4=81x^4y^4$

6 0

3 years ago