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3 years ago

the race is 20 minutes long. aritza gets a 5 meter head start after 2 minutes she is at 10 meters what is her equation

Mathematics

1 answer:

OlgaM077 [116]3 years ago

3 0

5+2+10 is what i thibnk the answer is

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Solve the following inequality.<br> 2x + 2(x+5) <+4(8 – 20)

Ilia_Sergeevich [38]

Answer:

x <-14.5

Step-by-step explanation:

2x + 2(x+5) <+4(8 – 20)

Distribute

2x+2x+10 < 4 (-12)

4x +10 < -48

Subtract 10 from each side

4x+10-10 <-48-10

4x< -58

Divide each side by 4

4x/4 < -58/4

x <-14.5

3 0

2 years ago

A quadrilateral with vertices (-3,2),(-5,-4), (4,6), and (7,0) is dilated by a scale factor of 0.5.

Ksenya-84 [330]

Original vertices:
1 (-3, 2)
2 (-5,-4)
3 ( 4, 6)
4 ( 7, 0)

dilated by a scale factor of 0.50

1) -3*0.50 = -1.5 ; 2 * 0.50 = 1 ⇒ (-1.5,1)
2) -5*0.50 = -2.5 ; -4*0.50 = -2 ⇒(-2.5,-2)
3) 4*0.50 = 2; 6*0.50 = 3 ⇒ (2,3)
4) 7*0.50 = 3.5; 0*0.50 = 0 ⇒ (3.5,0)

B.)
-1.5 -2.5 2 3.5
<span> 1 -2 3 0 </span>

6 0

3 years ago

Find the value of x, and please explain how you got x

katen-ka-za [31]

X equals to 48

The work is shown in the picture. I hope this helps.

8 0

2 years ago

Simplify √(49^8) ? a) 7√(5a^8) b) 7a^4 c)a√(24.5) d) 7a^8 please help as soon as possible.

WITCHER [35]

$\bf \sqrt{49^8}~~
\begin{cases}
49=7\cdot 7\\
\qquad 7^2
\end{cases}\implies \sqrt{(7^2)^8}\implies \sqrt{(7^8)^2}\implies 7^8\\\\\\ 5764801$

5 0

3 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

8 0

3 years ago