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Komok [63]
3 years ago
13

When a die is rolled three times, there are how many possible outcomes?

Mathematics
1 answer:
vlabodo [156]3 years ago
7 0
6 outcomes every roll, 6^3 = 216
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Answer/Step-by-step explanation:

Given, b(x) = (\frac{6}{7})^{x}

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When x = -2

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b(-2) = \frac{1}{(\frac{6}{7})^{2}}

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b(-2) = 1*\frac{49}{36}

b(-2) = \frac{49}{36}

When x = -1

b(-1) = (\frac{6}{7})^{-1}

b(-1) = \frac{1}{(\frac{6}{7})}

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b(-2) = \frac{7}{6}

When x = 0

b(0) = (\frac{6}{7})^{0}

b(0) = \frac{6^0}{7^0}

b(0) = \frac{1}{1}

b(0) = 1

When x = 1

b(1) = (\frac{6}{7})^{1}

b(1) = \frac{6}{7}

When x = 2

b(2) = (\frac{6}{7})^{2}

b(2) = \frac{6^2}{7^2}

b(2) = \frac{36}{49}

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3 years ago
1. Use the formula S(d)=√9.8d to calculate the estimated speed, in meters per second, of a tsunami if the disturbance occurred a
postnew [5]

Answer: 1. 210 meters per second .

2.  756  kilometers per hour.

Step-by-step explanation:

Given : The formula S(d)=\sqrt{9.8d} to calculate the estimated speed, in meters per second of a tsunami.

1. If the disturbance occurred at an ocean depth of 4,500 meters.

Then put d= 4500 in the above formula , we get

S(d)=\sqrt{9.8\times4500}

S(d)=\sqrt{44100}=\sqrt{21\times21\times10\times10}\\\\=\sqrt{210^2}=210

Hence, if the disturbance occurred at an ocean depth of 4,500 meters , the estimated speed would be 210 meters per second .

Also, A meter per second is equal to 3.6 kilometers per hour.

i.e. 1 meter per second = 3.6 kilometers per hour

Then by unitary method ,

210 meters per second  =3.6\times210 kilometers per hour

=756  kilometers per hour.

3 0
3 years ago
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