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Gnom [1K]
3 years ago
9

Which even number is a prime number​

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

Answer is 2

Step-by-step explanation:

The only even number which is a prime is 2. It is the smallest prime number. Except 2, all other prime numbers are odd numbers.

I hope it's helpful!

vichka [17]3 years ago
5 0

Answer:

2

Step-by-step explanation:

The only even number which is a prime is 2. It is the smallest prime number. Except 2, all other prime numbers are odd numbers.

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Pllllllzzzzzz gelpo me<br> aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Ilia_Sergeevich [38]

Answer:

D. DE = 24 yd, EF = 10 yd

Step-by-step explanation:

Solve for the unknown angles by setting up common ratios and cross multiplying. You can use this method because they are similar triangles.

For example, DE can be found by setting the ratios of AC/AB equal to the ratio of DF/DE.

13/12 = 26/x

Simply solve for x!

3 0
3 years ago
Read 2 more answers
Please check 1 and 2 and help with 3 and 4​
Sindrei [870]

I don't know the anwser sorry and what grade are u in

5 0
3 years ago
Use x = 1 to identify the value of each expression.
timofeeve [1]
1; 0; and for the last one x^3 x=cubic root of 3
7 0
3 years ago
Find the number of permutation of all the letters of the word "MULTIPLY".​
olga_2 [115]

Answer:

The answer is 40 320 ways.

Step-by-step explanation:

In permutation, object cannot be reuse and order matters.

So for this question, MULTIPLY can be arranged in many forms :

8P8 = 40 320

7 0
4 years ago
Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
4 years ago
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