By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.
<h3>How to prove this point lies on the unit circle?</h3>
In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 120
Reference angle = 60°.
For the coordinates, we have:
sin(-120) = -sin(60) = -1/2.
cos(-120) = -cos(60) = -√3/2.
By applying Pythagorean theorem, we have:
z² = x² + y²
z = √((-1/2)² + (-√3/2)²)
z = √(1/4 + 3/4)
z = √1
z = 1.
Read more on unit circle here: brainly.com/question/9797740
#SPJ1
Answer:
Um i think it would be
does not exist
Step-by-step explanation:
sorry if wrong im a little bad at that
Answer:
(a) -3.708
(b) 1.706
(c) 0.490
Step-by-step explanation:
The z-score of normal distribution is given as:
(a)
Given:
Score is, 
Mean value is, 
Standard deviation is, 
z-score is, 
(b)
Given:
Score is, 
Mean value is,
Standard deviation is,
z-score is, 
(c)
Given:
Score is, 
Mean value is,
Standard deviation is,
z-score is, 
The formula for the surface area of a cone is SA=(pi)(r^2)+(pi)(r)(l)
L is the slant height of the cone.
Because pi is in the answer choices, there is no need to multiply either by pi so the new formula becomes
SA=r^2+(r)(l)
Now you just plug in what you know
Sa=(8^2) + (8)(15)
Sa=64+120
Sa=184(pi)
*dont forget to put the pi back in since you took it out in the beginning of the equation*
Your answer is A.
Hope this helps :)
Answer: I had the same one
Step-by-step explanation: I DON'T GET IT EITHER
