I think y = (-23.8)
y=2+4.3x and let x=(-6) so y=2+(4.3 * -6) so y=2+ (-25.8) so y=2-25.8 so y= (-23.8)
The focal length of the given ellipse is given as (±6, 0)
<h3>Equation of an ellipse</h3>
An ellipse is defined as a regular oval shape, traced by a point moving in a plane so that the sum of its distances from two other points (the foci) is constant or when a cone is cut by an oblique plane which does not intersect the base.
The standard equation of an ellipse is expressed as;
x^2/a^2 + y^2/b^2 = 1
The formula for calculating the focus of the ellipse is given as:
c^2 = b^2 - a^2
Given the equation of an ellipse
(x-7)^2/64 + (y-5)^2/100 = 1
This can also be expressed as:
(x-7)^2/8^2 + (y-5)^2/10^2 = 1
Comparing with the general equation
a = 8 and b = 10
Substitute
c^2 = 10^2 - 8^2
c^2 = 100 - 64
c^2 = 36
c = 6
Hence the focal length of the given ellipse is given as (±6, 0)
Learn more on focus of ellipse here; brainly.com/question/4429071
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Answer:
2y-3x=10
Step-by-step explanation:
B
Step-by-step explanation:
YOU MULTIPLY EACH BY 2
Answer:
Step-by-step explanation:
Data:
r=4m
h=10m
w=? (3 m of water out top of the tank)
g=9.8m/s2
б=1000kg/m3
We must find the work necessary to move 3m of water from the top of the tank, so there is a differential (dy) that represents a small portion of volume for which it is integrated for the total volume to move then it would be the weight for the distance that is the volume to move
dw=weight*(10-y)dy, weight=б*V, , ⇒ weight=б*Vdy*g ⇒ dw=16πg(10-y)dy ⇒
evaluated between a and b, but a=10 and b=7 (last 3m of the full tank), finally
