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3 years ago

Can someone help with this question below?

Mathematics

2 answers:

Oxana [17]3 years ago

6 0

Answer:

C = 106.76 cm

Step-by-step explanation:

In the diagram, we are given the diameter (d), which is 34 cm. Using the formula you are given, we know circumference is 3.14 × d

C = 3.14 × d

C = 3.14 × (34)

C = 106.76 cm

The circumference is around 106.76 cm

mel-nik [20]3 years ago

4 0

The answer I c=106.76cm

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Find the slope of the line passing through the pairs of points and describe the line as rising, falling, horizontal or vertical.

Anna [14]

Answer:

$a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}$

Step-by-step explanation:

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

m > 0, then a line is rising

m < 0, then a line is falling

m = 0, then a line is horizontal

m is undefined, then a line is vertical

(2, 1) and (4, 5)

$m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}$

(-1, 0) and (3, -5)

$m=\dfrac{-5-0}{3-(-1)}=\dfrac{-5}{4}=-\dfrac{5}{4}$

(2, 1) and (-3, 1)

$m=\dfrac{1-1}{-3-2}=\dfrac{0}{-5}=0\to\text{horizontal}$

(-1, 2) and (-1, -5)

$m=\dfrac{-5-2}{-1-(-1))}=\dfrac{-7}{0}\ \text{UNDEFINED}\to\text{vertical}$

7 0

3 years ago

A company tests the life of its rechargeable batteries over six months of use. They test how long a battery will last after a fu

jonny [76]

Answer:

18.6 months

Step-by-step explanation:

Given that :

Best fit line from scatterplot :

y=-12.05x +224.26

x = Number of month

y = charge on battery

Number of months a typical battery uses before being dead completely :

When battery is dead completely ; charge =0, y = 0

y = -12.05x + 224.26

0 = - 12.05x + 224.26

12.05x = 224.26

x = 224.26 / 12.05

x = 18.610788

Hence, 18.6 months before battery is completely dead.

4 0

2 years ago

if a rental car costs Caden $35 for the day, plus $0.33 per mile and his total bill was $78, how many miles did he drive?

Digiron [165]

78-35= 43
43/.33= 130.30

130.3 miles

7 0

2 years ago

Solve 2x^3 - 3x^2 + 8x - 12 = 0 (this is complex zeros btw)

coldgirl [10]

Move all Terms to the left side and set equal to zero. Then set each factor equal to zero.

$x= \frac{3}2} , 2i , -2i$

7 0

3 years ago

(×-5) second power equals 3

Snezhnost [94]

Answer: $x_1=6.73\\\\x_2=3.26$

Step-by-step explanation:

Given the following expression:

$(x-5)^2=3$

And knowing that:

$(a\±b)^2=a^2-2ab+b^2$

We get:

$x^2-2(x)(5)+5^2=3\\\\x^2-10x+25=3$

Move the 3 to the left side of the equation:

$x^2-10x+25-3=0\\\\x^2-10x+22=0$

Apply the Quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$

In this case:

$a=1\\b=-10\\c=22$

Substituting values into the Quadratic formula, we get:

$x=\frac{-(-10)\±\sqrt{(-10)^2-4(1)(22)} }{2(1)}\\\\\\x_1=6.73\\\\x_2=3.26$

6 0

3 years ago