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SpyIntel [72]
2 years ago
9

Which method can you use to prove that the triangles are congruent

Mathematics
2 answers:
Natali [406]2 years ago
7 0

Answer:

HL

Step-by-step explanation:

It's a right triangle.

PolarNik [594]2 years ago
7 0

Answer: HL

Step-by-step explanation: because they are right triangles

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For the function f(x) = x2 ­ -12, find (f o f­-1)(4) A. 0 B. 4 C. 10 D. 6
slega [8]

We actually don't need to do any computation. By definition, the inverse function f^{-1} changes the role of input and output. So, if a function f maps x onto y, the inverse function maps y onto x.

You have to think like this: if the function makes a step further, the inverse function makes that same step back.

This means that the composition f \circ f^{-1} is always the identity function f(x) = x. In fact,

(f\circ f^{-1})(x) = f(f^{-1}(x)) = x

So, for every function, you have

(f\circ f^{-1})(4) = f(f^{-1}(4)) = 4

5 0
2 years ago
2x+y=10<br><br> x-intercept?______<br> y-intercept?______<br><br> have to show work
Wewaii [24]

Answer:

y = 10-2x

Step-by-step explanation:

2x+y=10

y=10-2x

3 0
2 years ago
What is the 10th term in the pattern with the formula 5n + 100?
yanalaym [24]
Easy
first term is n=1
so 10th term is n=10

5(10)+100=50+100=150

150 is 10th term
5 0
3 years ago
The area of a square is 225cm². On the map drawn to scale 1 : 3 find the area of the square​
Olin [163]

Answer:

25 cm^2

Step-by-step explanation:

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

Area if a square = length²

225 =  length²

length = √225

length = 15

if the map is drawn to scale of 1 : 3

the length on the map = 15/3 = 5

area of the square 5 x 5 = 25

8 0
3 years ago
A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
netineya [11]

Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

4 0
3 years ago
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