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Answer:
18" X 18" X 36"
Step-by-step explanation:
Given a square base container of height h, let a side of the base =s
The volume of the container,
If the sum of its height and girth (the perimeter of its base) equals 108 in
Substituting h=108-4s into V
We are required to determine the maximum volume of such container, first we take the derivative:
Optimizing:
Recall that: h = 108-4s
The dimensions of the carton are 18" X 18" X 36".
The vertex (minimum) of the quadratic ax² +bx +c is located at x=-b/(2a). This means the minimum value of f(x) will be found at x = -3/(2*1) = -1.5.
Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.
On the given interval, ...
the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057
Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.
On the given interval, ...
the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057