I got a domain and range of: ( − ∞ , 5 ) ∪ ( 5 , ∞ ) , or x ≠ 5 ( − ∞ , 1 ) ∪ ( 1 , ∞ ) , or y ≠ 1 The function is undefined for x values when the denominator, x − 5 , is 0 ; it's undefined to divide by 0 . Therefore, when x = 5 , f ( x ) is undefined. f ( 5 ) = 5 + 7 5 − 5 = 12 0 Since the domain is based on the allowed values of x , the domain is: ( − ∞ , 5 ) ∪ ( 5 , ∞ ) Based on the domain, we would find the range by solving for x in terms of f ( x ) , which we will write as y = f ( x ) . y = x + 7 x − 5 y ( x − 5 ) = x + 7 x y − 5 y = x + 7 x − x y = − 5 y − 7 x ( 1 − y ) = − 5 y − 7 x = − 5 y − 7 1 − y x = 5 y + 7 y − 1 This means when y = 1 , the function is undefined as well. So, the range is: ( − ∞ , 1 ) ∪ ( 1 , ∞ ) You can see that this is the case in the graph itself: graph{(x + 7)/(x - 5) [-73.3, 74.9, -37.07, 36.97]} What you should notice is the horizontal asymptote at y = 1 , and the vertical asymptote at x = 5 . Because the function is trying to reach an undefined value at those points ( x ≠ 5 , y ≠ 1 ), you get these "walls" that cannot be crossed, only ascended or descended from either side.
Since it takes her 2 1/2 miles to get to the aquarium from her hotel, you need to subtract the various distances from this value in order to find how long it took Clara to walk the rest of the way to the aquarium.
2 1/2 - (1/4+1 3/4)= 2 1/2 - 2= 1/2
Clara must walk 1/2 a mile to get the rest of the way to the aquarium.