I got a domain and range of: ( − ∞ , 5 ) ∪ ( 5 , ∞ ) , or x ≠ 5 ( − ∞ , 1 ) ∪ ( 1 , ∞ ) , or y ≠ 1 The function is undefined for x values when the denominator, x − 5 , is 0 ; it's undefined to divide by 0 . Therefore, when x = 5 , f ( x ) is undefined. f ( 5 ) = 5 + 7 5 − 5 = 12 0 Since the domain is based on the allowed values of x , the domain is: ( − ∞ , 5 ) ∪ ( 5 , ∞ ) Based on the domain, we would find the range by solving for x in terms of f ( x ) , which we will write as y = f ( x ) . y = x + 7 x − 5 y ( x − 5 ) = x + 7 x y − 5 y = x + 7 x − x y = − 5 y − 7 x ( 1 − y ) = − 5 y − 7 x = − 5 y − 7 1 − y x = 5 y + 7 y − 1 This means when y = 1 , the function is undefined as well. So, the range is: ( − ∞ , 1 ) ∪ ( 1 , ∞ ) You can see that this is the case in the graph itself: graph{(x + 7)/(x - 5) [-73.3, 74.9, -37.07, 36.97]} What you should notice is the horizontal asymptote at y = 1 , and the vertical asymptote at x = 5 . Because the function is trying to reach an undefined value at those points ( x ≠ 5 , y ≠ 1 ), you get these "walls" that cannot be crossed, only ascended or descended from either side.
The formula for the lateral area of a cylinder is LA = 2 x pi x r x h. (two times pi times radius times height) Using this formula, we can plug in the values and solve for the lateral area.
Plugging in the values: LA = 2 x pi x 7 x 9 Simplifying: LA = 2pi x 63 LA = 126pi yd^2
ANSWER: The 4th option - 126pi yd^2
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