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3 years ago

What is the area of the trapezoid

Mathematics

2 answers:

aniked [119]3 years ago

4 0

Answer:

180

Step-by-step explanation:

find the height by using pythagoras theorem

25²=7²+h²

h=24

then by using trapezium area formula, you will get it

$= \frac{1}{2} (4 + 11)(24)$

Sonbull [250]3 years ago

3 0

The area of a trapezoid is 180

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Please help me on number one I will mark you as the best answer

Fiesta28 [93]

Answer:

-4n - 40 > -120

<=> -4n > -80

<=> 4n < 80

<=> n < 20

=> Option B is correct.

q/(-7) + 1 > 5

<=> q/(-7) > 4

<=> q < 4 x (-7)

<=> q < -28

=> Option C is correct.

Hope this helps!

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3 years ago

Answer these three questions:

DanielleElmas [232]

Answer:

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Step-by-step explanation:

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3 years ago

Find all of the missing angles of sides of the triangle below. Note that side lengths are in centimeters. Show and/or explain yo

FromTheMoon [43]

Answer:

c=19.21

<C=90

<B=38.66°

<A=51.34

Step-by-step explanation:

12²+15²=c²

144+225=c²

c=19.21

<C=90

For angle B, the sinB=Opposite over Hypotenuse

sinB=12/19.21

sinB=0.62467

B=sin^-1(0.62467)

<B=38.66°

To find A, 180-90-38.66

<A=51.34

7 0

3 years ago

3x=54 Find a value for x that will make this equation true.

Luda [366]

A possible answer for x would be 18

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3 years ago

Read 2 more answers

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

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3 years ago