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tatyana61 [14]
3 years ago
10

How do you do this??

Mathematics
2 answers:
dedylja [7]3 years ago
7 0
Okay so:

200-45= 55 (meaning 55% are not plain)
55% of 200 is 110

So there are 110 bagels that aren't plain

Hope this helps fam
lisov135 [29]3 years ago
6 0
There is 78 plain bagels
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So how do you draw 2 degree angle ​
trapecia [35]
Make it a really small angle
3 0
3 years ago
Read 2 more answers
How are the solution sets to s<3 and |s|<3 different ?
Contact [7]

Answer:

they are different because of the mode sign on the second 's',

which if you are wondering what it stands for,

it represents only the magnitude of the value needed, not its sign,

let the assumed value of s be -5,

for example iin the first case, s < 3

hence s = -5, and it is true for s < 3

OR

if we take the second case, lsl < 3

that would be s = 5 [ not -5], which would not be true for lsl < 3

i hope u understood it,

if any more questions...please ask :)

8 0
3 years ago
Let f(x) = 5x + 6 and g(x) = -7x - 4. <br> Find f(x) + g(x)
sattari [20]
5x + 6 + (-7x - 4)

5x + 6 - 7x - 4

-2x + 2
4 0
3 years ago
What is the solution set of {x | x &lt; 2} {x | x ≥ 2}? all numbers less than -5 and greater than 5 the empty set the numbers be
juin [17]

Answer:

The solution set is the empty set.

Step-by-step explanation:

{x | x < 2} is the set of all numbers less than 2. This means x can take values such as 1.99, 0, -2000 and so on. That is, all values less than 2.

{x | x ≥ 2} is the set of all numbers equal to or greater than 2. This means x can take values such as 2, 2.1, 5000, and so on. That is, 2 or any value greater than 2.

Since there is no sign between the two sets, the question is asking for the intersection between these two sets. That is, what elements are common to these two sets? As we can see, the two sets don't have any common element. Hence, their intersection is the empty set.

(Note that the union of these two sets would be the set of all real numbers as that includes all elements from either set).

3 0
3 years ago
Use the Intermediate Value Theorem to show that the polynomial has a real zero between -4 and -1
hjlf
The answer is A
F (-4)=-23 < 0
F (-1)=16> 0
8 0
3 years ago
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