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nydimaria [60]
3 years ago
10

Find the critical value ze necessary to form a confidence interval at the level of confidence shown below

Mathematics
1 answer:
allsm [11]3 years ago
6 0

Answer:

1.31

Step-by-step explanation:

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Pavlova-9 [17]

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3 years ago
a previous analysis of paper boxes showed that the standard deviation of the length is 9mm. What is the 98% confidence interval
il63 [147K]
We cannot calculate the confidence interval without the sample size.  However, for the second question, the sample size needed would be 49.

The formula we use is

n=(\frac{z_{\frac{\alpha}{2}}\times \sigma}{E})^2

To find the z-score:
Convert 98% to a decimal:  0.98
Subtract from 1:  1-0.98 = 0.02
Divide by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is closest to a z-score of 2.33.

Using the z-score, our standard deviation (9) and our margin of error (3), we have:
n=(\frac{2.33(9)}{3})^2=(6.99)^2=48.86\approx 49
6 0
3 years ago
If the scale factor of a dilation is 4/3 the image will be a reduction of the pre-image, because 4/3 is a fraction less than one
Law Incorporation [45]
True and sorry if I’m incorrect
6 0
2 years ago
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