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3 years ago

Solve the equation. x−5(x−1)=x−(2x−3)

Mathematics

1 answer:

Sonja [21]3 years ago

6 0

Answer: = 2 /3

Step-by-step explanation: the explaination was too long but heres the answer ^

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The formula for this.(sorry for the horrible graph it was hand drawn

ozzi

Answer:

y = 1/2x+5

Step-by-step explanation:

5 0

3 years ago

Need help with this math problem

Shkiper50 [21]

In the figure, Blueline is Line AB and Redline is target line.

You can see that the target line does not pass through (18,-8)

Step-by-step explanation:

In the figure, Blueline is Line AB and Redline is target line.

You can see that the target line does not pass through (18,-8)

Taking a bottom-left corner of the graph as (0,0)

Given Line AB,

Point A is located as (4,9)

Point B is located as (16,1)

The slope of AB is

$=\frac{Y1-Y2}{X1-X2}$

$=\frac{9-1}{4-16}$

$=\frac{8}{-12}$

$=\frac{-2}{3}$

The question says " Draw a line passes through C(13,12) and parallel to Line AB "

Now, Let the equation of the target line is y=mx + c

Where m=slope and c is the y-intercept

The target line is parallel to the line AB

The slope of the Target line = The slope of the Line AB $=\frac{-2}{3}$

m= $=\frac{-2}{3}$

We can write, the equation of the target line is

$y=\frac{-2}{3}x + c$

Also, the Target line is passing through C(13,12)

Point C satisfies the equation

$y=\frac{-2}{3}x + c$

$12=\frac{-2}{3}13 + c$

$12=\frac{-26}{3} + c$

$12+\frac{26}{3}=c$

$c= 12+\frac{26}{3}$

$c= \frac{62}{3}$

Replacing the value

the equation of the target line is

$y=\frac{-2}{3}x + c$

$y=\frac{-2}{3}x + \frac{62}{3}$

$3y= -2x + 62$

It is also asked that if a line is extended , would it passes through the (18,-8)?

If a line passes through the point (18-,8) then, that point must satisfy the equation of a line

the equation of the target line is $3y= -2x + 62$

$3(-8)= -2(18) + 62$

$(-24)= (-36) + 62$

$(-24)= 26$

Left land side is not equal to right hand side.

Therefore. a line does not pass through the point (18,-8)

5 0

3 years ago

ASAP!! what is the polar form of -2sqrt3 -6i?

velikii [3]

Answer:

D on edge

Step-by-step explanation:

2020

4 0

3 years ago

Read 2 more answers

Let U be the 3 2 matrix [0.45 0.42, 0.25 0.35, 0.15 0.15]. The first column of U lists the costs per dollar of output for manufa

nika2105 [10]

Answer:

C. The 4 columns of UQ list the total costs for materials, labor, and overhead used to manufacture products B and C during the 4 quarters of the year.

Step-by-step explanation:

$U=\left\begin{array}{ccc}\\$Cost of Materials\\ $Cost of Labour\\ $Cost of Overhead\end{array}\right\left(\begin{array}{cc}$Product B&$Product C\\0.45&0.42\\ 0.25&0.35\\ 0.15&0.15\end{array}\right)$

$q_1$ is a vector in the set of real numbers $R^2$ that lists the output (measured in dollars) of products B and C manufactured during the first quarter of the year.

Therefore:

$UQ=\left\begin{array}{ccc}\\$Cost of Materials\\ $Cost of Labour\\ $Cost of Overhead\end{array}\right\left(\begin{array}{cc}$Product B&$Product C\\0.45&0.42\\ 0.25&0.35\\ 0.15&0.15\end{array}\right)\left(\begin{array}{ccc}q_{1B}\\q_{1C}\end{array}\right)\left(\begin{array}{ccc}q_{2B}\\q_{2C}\end{array}\right)\left(\begin{array}{ccc}q_{3B}\\q_{3C}\end{array}\right)\left(\begin{array}{ccc}q_{4B}\\q_{4C}\end{array}\right)$

$=\left(\begin{array}{c|c|c|c}q_1&q_2&q_3&q_4\\0.45q_{1B}+0.42q_{1C}&0.45q_{2B}+0.42q_{2C}&0.45q_{3B}+0.42q_{3C}&0.45q_{4B}+0.42q_{4C}\\0.25q_{1B}+0.35q_{1C}&0.25q_{2B}+0.35q_{2C}&0.25q_{3B}+0.35q_{3C}&0.25q_{4B}+0.35q_{4C}\\0.15q_{1B}+0.15q_{1C}&0.15q_{2B}+0.15q_{2C}&0.15q_{3B}+0.15q_{3C}&0.15q_{4B}+0.15q_{4C}\end{array}\right)$ Therefore, UQ has 4 columns and 3 rows.

The 4 columns of UQ list the total costs for materials(Row 1), labor(Row 2), and overhead(Row 3) used to manufacture products B and C during the 4 quarters of the year.

3 0

3 years ago

Factor x^2 – 7x + 10, 4x^2 – 81 and p (x) = 3x^3 – 12x

Leokris [45]

x^2 – 7x + 10 = (x-2)(x-5)

4x^2 – 81 = (2x-9)(2x+9)

3x^3 – 12x - 3x(x-2)(x+2)

6 0

4 years ago