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IRISSAK [1]
3 years ago
8

Chris requires three fifths liter of paint to complete a poster. He has one half liter of paint. Which equation can be used to f

ind the fraction of a liter of paint Chris still needs to complete the poster? (1 point) a the expression with the fractions three fifths minus one half is equal to the expression with the fractions three fifths minus one fifth is equal to the fraction two fifths b the expression with the fractions three fifths minus one half is equal to the expression with the fractions three tenths minus one tenth is equal to the fraction two tenths c the expression with the fractions three fifths minus one half is equal to the expression with the fractions three fifths minus two fifths is equal to the fraction one fifth d the expression with the fractions three fifths minus one half is equal to the expression with the fractions six tenths minus five tenths is equal to the fraction one tenth
Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

d the expression with the fractions three fifths minus one half is equal to the expression with the fractions six tenths minus five tenths is equal to the fraction one tenth

Step-by-step explanation:

Chris requires three fifths liter of paint to complete a poster. He has one half liter of paint. Which equation can be used to find the fraction of a liter of paint Chris still needs to complete the poster?

The fraction of a liter Chris requires to complete his painting is given as:

3/5 liter = 1/2 liter + x

x = 3/5 - 1/2

Lowest Common Denominator = 10

x = 6 - 5/10

x = 1/10

option d is the correct option.( the expression with the fractions three fifths minus one half is equal to the expression with the fractions six tenths minus five tenths is equal to the fraction one tenth)

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IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

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3 years ago
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The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

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Analysis:

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For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

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Model 2

Diagonal= 37cm, radius = 6cm  lateral height = 35cm

(37)^{2} = (35)^{2}+ (6)^{2}

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Model 3

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(60)^{2} = (20)^{2} + (40)^{2}

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Therefore the lateral surface model 1 meets the base at right angle

In conclusion,  the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

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