Does this graph represent a function? Why or why not?

Find the 95% confidence interval for estimating the population mean μ

AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

$\displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}$

We are given these variables:

$\overline{x}=50$
$n=60$
$\sigma=10$

Plug these values into the formula for the confidence interval:

$\displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}$

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

$\displaystyle \frac{1-C}{2}=A$

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

$\displaystyle \frac{1-.95}{2}=.025$

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

$t^*=1.96$

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

$\displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}$

We can calculate the confidence interval, using this formula, to be:

$\boxed{(47.4697, \ 52.5303)}$

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0

1 year ago

Watch help video

amm1812

Answer:

Step-by-step explanation:

25 - 32 = -7 and 18 - 25 = -7

It means an arithmetic sequence with common difference d = -7

$a_n = a_1+d(n-1)\\\\a_1=32\\d=-7\\\\a_n=32+(-7)(n-1)\\\\a_n = 32-7n+7\\\\\underline{a_n=-7n+39}$

4 0

3 years ago

Theoretical probability is the probability that an event occurs when all of the outcomes of the experiment are equally likely.

MA_775_DIABLO [31]

1. The probability that we select a red marble is 1/3.

We found this out by taking the amount of red marbles there are and the total amount of marbles. The total amount of marbles is 18 and there are red marbles. So, it would become 6 out of 18 or 6/18. Then, we simplify 6/18 to the simplest form. The greatest common factor of both of those numbers is 6. Lastly, we divide each of them by 6 to get the simplest form.

6/18 = (6/6)/(18/6)

(6/6)/(18/6) = 1/3

So, therefore, the theoretical probability of picking a red marble is 1/3.

2. The probability that we select a blue marble is 2/3.

We can find this out by taking the amount of blue marbles there are and the total amount of marbles. We know that the total amount of marble is 18 and there are 12 blue marbles. So, we simply get the GCF (greatest common factor) and divide them by it.

Greatest Common Factor of 12 and 18 = 6

12/18 = (12/6)/(18/6)

(12/6)/(18/6) = 2/3

Thus, the theoretical probability of picking a blue marble is 2/3.

4 0

3 years ago

Who started the problem correctly? The problem form is (-5) - (-1 3/4).

Veronika [31]

Answer:

Shane started the problem correctly

Step-by-step explanation:

We are given problem (-5) - (-1 3/4).