Answer:
64q^6r^8s^4
Step-by-step explanation:
(-8q^3r^4s^2)^2
= (-8)^2 q^(3*2) r^(4*2) s^(2*2)
= 64q^6r^8s^4
6y^2-7y-3-2y^2+9y+7 (pretend that you're multiplying -1 to 2y^2-9y-7 which is why 9y and 7 are positive now).
Now you're able to simplify your problem, so...
6y^2-2y^2= 4y^2
-7y+9y= 2y
-3+7=4
4y^2+2y+4
Might want to check my math but that's how you do it.
Two planes intersect at a line. Not a point.
Answer:
(x-5)² + y² = 4
Step-by-step explanation:
formula of circle: (x-h)² + (y-k)² = r² where (h,k) is coordinate of center and r is radius
center: (5 , 0) r = 2
Equation: (x-5)² + y² = 4
In the left/right direction, your circle (at it's biggest point) goes from -5 to 5
the middle of -5 and 5 is 0
so the center of your circle should have a x = 0
in the (x , y) point
the only option that has
(0, something)
is C
Therefore your answer is C
