Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Answer:
THE PICTURE IS TO SMALL
Step-by-step explanation:
!!!!!!!!
Answer:
15 divided by 1/5 is equal to 1.
C. 15
-1 is not a natural number so B is not your answer
0.5 is not a whole number so D is not your answer
0 is not a natural number so A is not your answer
Answer:
45
Step-by-step explanation:
add 15 on both sides