Answer:
$4,455
Explanation:
The computation of total decrease in earnings (pretax) in Morris Dec. 31, 2021, income statement is given below:-
Interest expense upto 31 Dec 2021 = (Total present value of lease payment - Lease payment on July 1, 2021) × 6% × 6 ÷ 12
= ($58,500 - $7,500) × 6% × 6 ÷ 12
= $51,000 × 6% × 6 ÷ 12
= $1,530
Depreciation expense upto 31 Dec 2021 = Fair value of equipment ÷ Useful life × 6 ÷ 12
= $58,500 ÷ 10 × 6 ÷ 12
= $5,850 × 6 ÷ 12
= $2,925
So, the total decrease in earnings (pretax) in Morris Dec. 31, 2021, income statement = Interest expense upto 31 Dec 2021 + Depreciation expense upto 31 Dec 2021
= $1,530 + $2,925
= $4,455
Answer:
The issue price of the bond is $ 487,598 as calculated in the attached
Explanation:
The issue price of the bond is the present value of the future cash flows payable by the bond.The discount factor with which to multiply the future cash flows to arrive at present value is modified by dividing the rate by 2 to show that interest is payable semi-annually and also by multiplying n, the number of years by 2 to indicate that the interest would now be paid at a time that doubles the original time horizon.
The formula for present value in the case is :FV/(1+10%/2)^n*2
In calculating the present of coupon interest received in the first six months,the coupon interest is calculated $520000*9%/2=$23400,then the present of this amount is gotten by multiplying $23400 with (1+10%/2)^1*2
Find detailed computation in the attached.
The par value of $520000 is added to the last interest as it payable then.
Loose valuable customers
Loose the trust of the people
The business might run a loss
Answer:
Maximum initial cost would be $58,116,883.12
Explanation:
1,790,000 increased at 3%
Ke 0.119 + 0.02 = 0.139
ER 0.15
Kd(after-tax) Kd(1-t) = 0.047
DR 0.85
WACC 0.06080
Now that we have the rate, we calculate the present value using the gordon method
1,790,000 / (0.06080-0.03) = 58,116,883.12
Answer:
$24.7million
$97.86million
$9.89million
Explanation:
From the sample , the lowest number is 16.3 and the highest number is 41, the range is
41-16.3
=$24.7 million
Σ 
In the sample given the mean is . : (41 +40 +38+ 32+ 23+ 22+ 20+ 18+ 17.8 +16.3 )/10
mean=26.81
Using that, we can find the variance:
[(41-26.81)^2+(40-26.81)^2+(38-26.81)^2+(32-26.81)^2+(23-26.81)^2+(22-26.81)^2+(20-26.81)^2+(18-26.81)^2+(17.8-26.81)^2+(16.3-26.81)^2]/10=97.86million
The standard deviation is just the square root of the variance:
standard deviation=√(var)
, the standard deviation is the square root of 97.86, which equals $ 9.89 million
