Solve 3(z+1) + 11 < -2(z+13)

Mathematics

1 answer:

MatroZZZ [7]3 years ago

4 0

Answer:

The answer is z < -8. First of all, you use distributive property to get rid of the brackets. 3(z) = 3z and 3(1) = 3. The left side of the equation is now 3z + 3 + 11. Then, on the other side, -2(z) = -2z and -2(13) = -26. The right side of the equation is now -2z - 26. Then we combine like terms on the left side so we end up with 3z + 14 while the other side is still -2z - 26. We can put all of the z on the left side, so add 2z to both sides and then we have 5z + 14 < -26. We can put all of the “regular” numbers on the right side, so subtract 14 from each side and then we have 5z < -40. Divide each side by 5 and you end up with z < -8!

Step-by-step explanation:

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miv72 [106K]

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Step-by-step explanation:

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6 0

2 years ago

Please Help me. Also if you could show your work thatd be great.

Over [174]

Answer:

3) $all \: real \: numbers$ , $( - \infty , \infty )$ , or $- \infty \leqslant x \leqslant \infty$ (same thing)

4) $- \infty < y < 0$ or $( - \infty ,0)$ (same thing)

5) $-2$ or $(0, -2)$ (same thing)

Step-by-step explanation:

3) Domain represents the amount of $x$ -values in a function. The image shows that the function's arrows point in both directions (right and left), infinitely, so the domain would be $all \: real \: numbers$ , $( - \infty , \infty )$ , or $- \infty \leqslant x \leqslant \infty$ (same thing).

4) Range represents the amount of $y$ -values in a function. The function goes downward forever ( $- \infty < y$ ) by the indication of an arrow and halts just under the y-axis ( $y < 0$ ). After combining these two inequalities, you see that the range is $- \infty < y < 0$ or $( - \infty ,0)$ (same thing).