A package of twelve cans of black beans cost $6.84. What is the cost of 5 can of black

(x+5)(x-5) Multiplying special case polynomials

azamat

Answer:

x^2 - 25 ✔

Step-by-step explanation:

(x+5)(x-5)

x(x-5) +5(x-5)

x^2 - 5x + 5x - 25

x^2 - 25

7 0

4 years ago

The owner of a small restaurant bought 75 kilograms of rice. Each week, the restaurant uses 4.5 kilograms of rice.

leva [86]

Answer:

6 weeks 27kilo

12 weeks 54 kilo

Step-by-step explanation:

4.5*12=54

4.5*6=27

3 0

3 years ago

The sides of a triangle are 7, 4, n. If n is an integer, state the largest and smallest possible values of n. smallest value- la

VLD [36.1K]

The smallest value it could be is 4 and the largest value it could be is 10.

The triangle inequality theorem states that any two sides of a triangle must have a sum greater than the third side. Given the two sides we have, 7 and 4, the sum would be 11; this would mean that the missing side could be no more than 10.

If we take the unknown side and the smallest one we're given, we would have the inequality
n+4>7

Subtracting 4 from both sides we would have n>3. That means it would have to be the next integer up, which would be 4.

8 0

3 years ago

A shop sells packs of black pens, packs of red pens and packs of green pens.

olchik [2.2K]

Answer:

85 pens

Step-by-step explanation:

The computation of the number of green pens sold is shown below;

As the number of black pens, red pens, and green pans is 3:5:6

And, the ratio of sold of black pens, red pens, and green pans is 7:3:4

So, the ratio of pens in a number of pens is

= 3 × 7 : 5 × 3 : 4 × 6

= 21: 15 : 24

= 7: 5 : 8

And, the total of 212 pens are sold

So, the number of green pens sold is

= 8 × 212 ÷ (7 + 5 + 8)

= 85 pens

4 0

3 years ago

1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into

iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

$(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133$

As only 1466 gives a possible result (no decimals), this is the amount of soldiers left.

The deserters are 34:

$D=1500-1466=34$

6 0

3 years ago