Answer:
Probability that detector B goes off is '0.615'
Step-by-step explanation:
Given that:
1) Probability that detector A goes off and detector B does not go off is 0.25.
2)Probability that detector A does not go off is 0.35.
3)Probability that detector A goes off is (1-0.35)=0.65
Assuming that
Probability that detector B goes off is 'p' Hence the probability that detector B does not goes off is (1-p)
Thus the probability that detector A goes off and detector B does not go off is product of the individual probabilities
Probability that detector B goes off is '0.615'
