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4 years ago

1and1/4 x 1and1/4 equals what

Mathematics

1 answer:

Angelina_Jolie [31]4 years ago

8 0

Answer:

1/2

Step-by-step explanation:

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Chinedu sat down to do his homework, which included 30 math problems. He solved 2 problems each minute. Let f(n) be the number o

vova2212 [387]

Answer:

It would be an arithmetic sequence.

Step-by-step explanation:

This is because during each minute, he does another 2 problems. Or, in other words +2 each minute.

This is the result of the sequence during each minute:

(Problems Left): <em>30, 28, 26, 24, 22... 0</em>

Time (Minutes) --->

If it was instead a geometric equation, it would go by a multiple, such as the number 2. Or, ×2 each minute.

During the first minute, he learns 2 problems. But then as each minutes passes it turns into 4, then 8, and etc..

This is the result of the pretend sequence during each minute: (Problems Left): <em>30, 28, 24, 16, 0</em>

Time (Minutes) --->

The formula would be for this equation would follow

an = a1 + (n-1)d

an is your result.

a1 is the first number you plug in

(n-1) is just there, don't mind it (aka: the term position).

and d is the rate.

So just plug them in from your equation, and you would get this:

an = 30(n-1)2

6 0

3 years ago

What is the equation of the circle whose diameter has endpoints (8,-2) and (-2,6)?

klemol [59]

Answer:

$(x-3)^{2} +(y-2)^{2}=41$

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(8,-2)\\E(-2,6)$

substitute the values

$d=\sqrt{(6+2)^{2}+(-2-8)^{2}}$

$d=\sqrt{(8)^{2}+(-10)^{2}}$

$d=\sqrt{164}\ units$

$d=2\sqrt{41}\ units$

step 2

Find the center of the circle

The center is the midpoint of the diameter

The center is equal to

$C=(\frac{8-2}{2},\frac{-2+6}{2})$

$C=(3,2)$

step 3

Find the equation of the circle

The equation of the circle in center radius form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

we have

(h,k)=(3,2)

$r=2\sqrt{41}/2=\sqrt{41}\ units$ ---> the radius is half the diameter

substitute

$(x-3)^{2} +(y-2)^{2}=(\sqrt{41})^{2}$

$(x-3)^{2} +(y-2)^{2}=41$

4 0

4 years ago

Q2: How do you identify which fractions will have repeating decimals?

sdas [7]

If there is a fraction with more then one of the same number repeated behind the decimal, it is a repeating decimal

3 0

3 years ago

Please solve, due tomorrow!

Darya [45]

5x=25 X= 5
X/3=7 X= 21
2x=14 X= 7
x/2=12 X=6
x/4=6 X=24

4 0

4 years ago

Help! Thank you so much!!

AveGali [126]

Your final answer is -8

5 0

3 years ago