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3 years ago

Plsss helppp with my math!!

Mathematics

1 answer:

Deffense [45]3 years ago

8 0

A. 4
b. 4
c. 9
d. 3
e. 8
f. 9
g. 14
h. 11

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If you know that 4 times 5 equals 20 how can you use the commutave property of multiplication to find 5 x 4

const2013 [10]

Yes, because you can multiply the numbers. Example: Use commutative property of multiplication to rewrite 5 x 4 5 x 4 Answer: 4 x 5.

8 0

3 years ago

A tax is a restaurant charge based on a percentage of each meal price. The expression shown represents the tax on a meal price,p

tiny-mole [99]

Answer:

56=90=21

Step-by-step explanation:

8 0

3 years ago

I WILL MARK BRAINLIEST IF CORRECT! Click on the graph below to create a pentagon with vertices at the following points.

Andrei [34K]

Answer:

Looks good to me.

Step-by-step explanation:

Looks good to me.

5 0

3 years ago

Read 2 more answers

Write a linear equation. Explain it in number please! 20 points!!!

juin [17]

To find a linear question, we must have two points on the line and we must know the slope.

Let us choose two points at random:

(-6,12) and (-5,14)

Now let us find the slope of the linear line:

$m = \frac{y2-y1}{x2-x1} =\frac{14-12}{-5--6} = 2$

So the slope is 2.

Now let us set up the equation which now requires only one point and the slope

let us use the point (-6,12) and the slope of 2

$y-12 = 2(x+6)\\y = 2x +12 +12\\y= 2x +4$

So the linear line is y = 2x + 4.

Hope that helps!

8 0

2 years ago

Please help me solve this

Viktor [21]

You can factor the 32 out of the sum:

$\displaystyle \sum_{m=1}^\infty 32 \cdot \left(\dfrac{1}{2}\right)^{m-1} = 32\sum_{m=1}^\infty \left(\dfrac{1}{2}\right)^{m-1}$

We can also change the index as follows

$\displaystyle 32\sum_{m=1}^\infty \left(\dfrac{1}{2}\right)^{m-1} = 32\sum_{m=0}^\infty \left(\dfrac{1}{2}\right)^{m}$

Now, we have a theorem that states that the series

$\displaystyle \sum_{m=1}^\infty a^m$

converges if and only if $|a|$ , and in this case we have

$\displaystyle \sum_{m=1}^\infty a^m = \dfrac{1}{1-a}$

This is your case, because you have

$|a|=\dfrac{1}{2}$

which implies that your series converges, and the value is

$\displaystyle 32\sum_{m=0}^\infty \left(\dfrac{1}{2}\right)^{m} = 32 \cdot \dfrac{1}{1-\frac{1}{2}} = 32\cdot 2 = 64$

3 0

3 years ago