Answer:
14.2cm
Step-by-step explanation:
Complete question:
<em>In circle O, the length of radius OL is 6 cm and the length of arc LM is 6.3 cm. The measure of angle MON is 75°. </em>
<em>Rounded to the nearest tenth of a centimeter, what is the length of arc LMN? </em>
<em></em>
Find the diagram attached
arc LN= arc LM + arc MN
First we need to get the arc MN
length of an arc = theta/360 * 2πr
length of arc MN = 75/360 * 2(3.14)(6)
length of arc MN = 0.20833*37.68
length of arc MN = 7.85
Hence;
arc LN = 6.3 + 7.85
arc LN = 14.15cm
Hence the length of arc LN is 14.2cm
Answer:
75.5102040816%
Step-by-step explanation:
so the answer is 75% or 75.5%
37 x 100 =3,700
3,700 ÷ 49 =75.5102040816% so the actual answer is 75% bc they want you to round but its 6 and above to round up do you round down to 75%
Answer:
y = -x - 6
Step-by-step explanation:
Given:
From:

where m = slope and b = y-intercept. Therefore:

Since the equation passes through a point (2,-8). Substitute x = 2 and y = -8 in and solve for b:

Then substitute b-value in the equation:

Hence, the equation is y = -x - 6
Answer:
a. 5 sets of tires
b. 16 times
Step-by-step explanation:
total distance commuted by the truck = 160,000 miles
a.tires of the truck are changed after every 40,000 miles
40,000 to 80,000 to 120,000 to 160,000 he will change his tires four times assuming he started his journey with the new tires. so, he needs uses a total of 5 sets of tires for the whole journey.
b. changes oil every 10,000 miles then to travel 160,000 miles
= 
= 16 times in whole journey
We are given 8 h's and 2 t's.
A permutation of these letters is simply an arrangement in a row.
For example:
h h h t h h t h h h
or
h t h h h h h h t h
The number of arrangements is equal to the number of pairs of positions we fix for t, the rest of the positions are filled with h:
these positions are :
(1, 2), (1, 3), (1,4)..... (1, 10)
(2, 3), (2,4)..... (2, 10)
(3,4).... (3,10)
(9,10)
so the 1st position combined with any of the remaining 9
the 2 position combined with any of the remaining 8
...
the 9th position combined with the remaining 1
this makes 9+8+7+6+5+4+3+2+1=45 positions to place the 2 t's.
Remark: the number of positions for the 2 t's could also have been calculated by C(10, 2)=10!/(8!2!)=(10*9)/2=45
Answer: 45