Answer:
1440
Step-by-step explanation:
It’s 1440
Answer: Explanatory variable = " number of times the owner has an advertisement played on the radio"
Response variable = "number of new customers who will visit a shop"
Step-by-step explanation:
- An explanatory variable is a kind of independent variable that can be manipulated by researcher in a study to check the response of the response variable.
In the given situation , the business owner is predicting the number of new customers who will visit a shop based on the number of times the owner has an advertisement played on the radio.
Here , He is controlling the advertisement played on the radio to see the response of customers.
Therefore ,
Explanatory variable = " number of times the owner has an advertisement played on the radio"
Response variable = "number of new customers who will visit a shop"
Answer:
Step-by-step explanation:
Answer:
0.0181 probability of choosing a king and then, without replacement, a face card.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability of choosing a king:
There are four kings on a standard deck of 52 cards, so:
![P(A) = \frac{4}{52} = \frac{1}{13}](https://tex.z-dn.net/?f=P%28A%29%20%3D%20%5Cfrac%7B4%7D%7B52%7D%20%3D%20%5Cfrac%7B1%7D%7B13%7D)
Probability of choosing a face card, considering the previous card was a king.
12 face cards out of 51. So
![P(B|A) = \frac{12}{51}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7B12%7D%7B51%7D)
What is the probability of choosing a king and then, without replacement, a face card?
![P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%20P%28A%29P%28B%7CA%29%20%3D%20%5Cfrac%7B1%7D%7B13%7D%20%5Ctimes%20%5Cfrac%7B12%7D%7B51%7D%20%3D%20%5Cfrac%7B1%2A12%7D%7B13%2A51%7D%20%3D%200.0181)
0.0181 probability of choosing a king and then, without replacement, a face card.
For the first one just do the multiplication as you do normally.
For the second one, you have to put a zero behind before calculating the numbers in front