Using row 4:
<span>coefficients are: 1, 4, 6, 4, 1 </span>
<span>a^4 + a^3b + a^2b^2 + ab^3 + b^4 </span>
<span>Now adding the coefficients: </span>
<span>1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4 </span>
<span>Substitute a and b: </span>
<span>a = 4x </span>
<span>
b = -3y </span>
<span>1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 </span>
<span>Now simplify the above: </span>
<span>256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4 </span>
I’m personally not to good at adding fractions so I turned 1/10 into 0.1
Then I divided 268.4 by .1 and got 2,674.
Combine like terms:
subtract x from both sides to get
2x+5=14
subtract 5
2x=9
isolate x:
divide 2 from both sides to isolate x
x=9/2
that's your final answer. unless your teacher wants you to put it in decimal form in which all you do is divide 9÷2.
I know this one give me like 5 minutes
<span>
You can write the equation in point-slope form, which has the format <em>y-y</em>subscript1=<em>m</em>(<em>x-x</em>subscript1), with <em>y</em>subscript1 and <em>x</em>subscript1 being the y and x coordinates for a point on the line, and <em>m</em> being the slope. </span>
<span /><span>Substitute a y and x coordinate into the equation so you have <em>y</em>-6=<em>m</em>(<em>x</em>-2)</span>
<span /><span><span>Then find the slope so you can replace <em>m</em>. The slope formula is <em />(<em>y</em>subscript2-<em>y</em>subscript1)/(<em>x</em>subscript2-<em>x</em>subscript1). </span><span>Substitute the coordinates in so you have <em>m</em>=(16-6)/(4-2), which simplifies to 10/2 and then 5.</span></span>
<span><span /></span><span>Now the equation is <em>y</em>-6=5(<em>x</em>-2)</span>
<span />If you want a different form, for example slope-intercept form, you can change it to that:
<span><em>y</em>-6=5(<em>x</em>-2)</span>
<span><em>y</em>=5x-4</span>
