Answer:
x = int(input("Enter an integer: "))
y = int(input("Enter another integer: "))
if x > y:
for number in range(y+1, x):
print(number, end=" ")
elif y > x:
for number in range(x+1, y):
print(number, end=" ")
else:
print("There are no integers between {} and {}".format(x, y))
Explanation:
*The code is in Python.
Ask the user to enter the two integers, x and y
Since we want our program to run regardless of which entered value is larger, we need to compare the numbers to be able to create the loop that prints the numbers.
Check if x is greater than y. If it is, create a for loop that iterates from y+1 to x-1 and print the numbers
Otherwise, check if y is greater than x. If it is, create a for loop that iterates from x+1 to y-1 and print the numbers
If none of the previous part is executed, print that there are no integers between
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Answer:
- You need to create a variable outside (before) the input loop.
- You need a variable inside your loop that temporarily holds the user input.
- In your loop, you will compare if the variable outside the loop is greater than (or less than) the new user input.
I don't know what program language you are using, but I will use python since it's easy to read and you will get the idea if you're using a different programming language.
<u>Code (Python)</u>
largestnum = 0
for x in range(6): <em>#loops 6 times</em>
newnum = int(input("Enter a number: ")) #ask user for input & converts to int.
if newnum > largestnum: <em>#if new number is greater than largest num </em>
largestnum = newnum <em>#make it the largest number</em>
<em> </em>print("Largest:", largestnum)
The reason why you need a variable outside of the loop is because after the loop is done all variables inside the loop are trashed and can no longer be accessed outside of the loop.
Maybe it's because he hasn't set up the new system once he does that then he should be able to function it but if he is still having trouble then he could call the company or ask for refund
