We have to develop a 90% confidence interval for the proportion of all students at the college that have met with a counselor to develop an educational plan.

We have a sample of size 25, where the sample proportion is:

$p=X/n=17/25=0.68$

The critical value of z for a 90% CI is z=1.645.

The margin of error is then:

$E=z\cdot\sqrt{\dfrac{p(1-p)}{n}}=1.645*\sqrt{\dfrac{0.68*0.32}{25}}=1.645*\sqrt{0.008704}=1.645*0.093\\\\\\E=0.15$

Then, the lower and upper bound of the confidence interval are:

$LL=\hat p-E=0.68-0.15=0.53\\\\UL=\hat p+E=0.68+0.15=0.83$

The 90% CI for p is (0.53, 0.83)

8 0

3 years ago

The store has 28 notebooks in packs of 4. Three packs of notebooks are sold. How many packs of notebooks are left?

alukav5142 [94]

28/4=7x3=21 so 28-21=7 notebooks left

7 0

3 years ago

(2 3/8 +1 1/4)+ 2 7/8 using properties of addition

irina1246 [14]

Answer:

Well The answer is: 9

Step-by-step explanation:

(2 3/8 + 11/4)=

(2 + 3) + (3/8 + 3/4)= 6 1/8

(6 1/8 + 2 7/8) =

(6 + 2) + (1/8 + 7/8) = 9

Pls give me brainliest i hope this helped

4 0

3 years ago

Vector's map has the scale missing. He know that the distance from the lake to the youth center is 8 miles. On the map, they are

Lorico [155]

1inch= 4miles

8 miles / 2 inches = 4miles per inch

4 0

3 years ago

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