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3 years ago

Can someone help me with this problem?

Mathematics

1 answer:

Anika [276]3 years ago

4 0

16 : 80
x : 100

Cross multiply.

80× = 100×16
× = 100 × 16 /80
× = 20 grams.

His allowance is 20g of saturated fat.

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Write the ordered pair that represents MP. Then find the magnitude of MP.

jarptica [38.1K]

Answer:

(23,-4): $\sqrt{545}$ units

Step-by-step explanation:

We are given that M(-19,4)and P(4,0)

We have to find the ordered pair that represents MP and find the magnitude of MP.

MP=P-M

MP=(4,0)-(-19,4)=(4+19,0-4)

MP=(23,-4)

Magnitude of MP= $\sqrt{(23)^2+(-4)^2}$

Magnitude of MP= $\sqrt{529+16}$

Magnitude of MP= $\sqrt{545}$ units

Hence, .option c is true.

Answer:c.(23,-4): $\sqrt{545}$ units

5 0

2 years ago

Helppppppp me pls :)

fredd [130]

Answer:

3.6

Step-by-step explanation:

5 0

3 years ago

If the area of a square with side x is equal to the area of a triangle with base x, then find the altitude of the triangle.

zhannawk [14.2K]

Answer:

$h= 2x$

Step-by-step explanation:

Given

Square

$Side = x$

Triangle

$Base = x$

$Altitude = h$

Required

Find h, if both shapes have the same area

The area of the square is:

$Area = x * x$

$Area = x^2$

The area of the triangle is:

$Area = \frac{1}{2} * Base*Height$

$Area = \frac{1}{2} * x*h$

Equate both areas

$x^2 = \frac{1}{2} * x*h$

Divide both sides by x

$x = \frac{1}{2} *h$

Multiply both sides by 2

$2*x = \frac{1}{2} *h*2$

$2x = h$

$h= 2x$

3 0

2 years ago

The quotient obtained when an integer is divided by its additive inverse is ________________.

LenaWriter [7]

Answer: -1

Step-by-step explanation: Let the integer be x

It's additive inverse = -x

= x / -x = -1

7 0

2 years ago

PLEASE ANSWER THIS: look at the pic for question. Thanks!!!

Nadya [2.5K]

Answer:

$\text{D. }b^2-4ac>0$

Step-by-step explanation:

The equation $b^2-4ac$ represents the discriminant of a quadratic. It is the part taken from under the radical in the quadratic formula.

For any quadratic:

If the discriminant is positive, or greater than 0, the quadratic has two solutions

If the discriminant is equal to 0, the quadratic has one distinct real solution (the solution is repeated).

If the discriminant is negative, or less than 0, the quadratic has zero solutions

In the graph, we see that the equation intersects the x-axis at two distinct points. Therefore, the quadratic has two solutions and the discriminant must be positive. Thus, we have $b^2-4ac>0$ .

4 0

2 years ago