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3 years ago

Can someone help me with this problem?

Mathematics

1 answer:

Anika [276]3 years ago

4 0

16 : 80
x : 100

Cross multiply.

80× = 100×16
× = 100 × 16 /80
× = 20 grams.

His allowance is 20g of saturated fat.

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an item is regularly priced at $90 . alan bought it on sale for 30% off the regular price. how much did alan pay?

Minchanka [31]

Answer:

$63

Step-by-step explanation:

100-30=70%

0.7*90=63

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3 years ago

Gardeners planted bushes in the city park. They wanted 1/3 of the bushes to be rose bushes and 1/4 of the rose bushes to be pink

den301095 [7]

3/4

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3 years ago

Read 2 more answers

What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^2-4}\right) dx d ( 3x 2 −4 2x+3 )start fraction, d, divided by, d, x

stellarik [79]

Answer:

Step-by-step explanation:

We are asked to find the value of expression $\frac{d}{dx}(\frac{2x+3}{3x^2-4})$ at $x=-1$ .

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

$(\frac{f(x)}{g(x)})'=\frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{(g(x))^2}$

$\frac{d}{dx}(\frac{2x+3}{3x^2-4})$

$\frac{\frac{d}{dx}(2x+3)*(3x^2-4)-(2x+3)*\frac{d}{dx}(3x^2-4)}{(3x^2-4)^2}$

$\frac{2*(3x^2-4)-(2x+3)*(6x)}{(3x^2-4)^2}$

$\frac{6x^2-8-12x^2-18x}{(3x^2-4)^2}$

$\frac{-6x^2-18x-8}{(3x^2-4)^2}$

Therefore, our required derivative is $\frac{-6x^2-18x-8}{(3x^2-4)^2}$ .

Now, we will substitute $x=-1$ in our derivative to find the required value as:

$\frac{-6(-1)^2-18(-1)-8}{(3(-1)^2-4)^2}$

$\frac{-6(1)+18-8}{(3(1)-4)^2}$

$\frac{-6+18-8}{(3-4)^2}$

$\frac{4}{(-1)^2}$

$\frac{4}{1}$

$4$

Therefore, the value of expression $\frac{d}{dx}(\frac{2x+3}{3x^2-4})$ at $x=-1$ is 4.

6 0

3 years ago

Find the slope (-9,-10), (6,0)

mote1985 [20]

Step-by-step explanation:

at one point that where all a six

4 0

3 years ago

5: Using his telescope, Tommy watches a bald eagle as it sits on the top of a cliff. The telescope is positioned so thät the of

ExtremeBDS [4]

The telescope the cliff and the eagle will from a right tingle as you can see in the picture. The distance between the base of the cliff an the telescope will be the adjacent side of the elevation angle.
The opposite side of the elevation angle will be the height of the cliff 1.3 meters above the ground.
Now, to find the opposite side, $a$ , of our elevation angle, we are going to use the trig function tangent:
$tan(38)= \frac{a}{116}$
$a=116tan(38)$
$a=90.6$

Finally, we are going to add the height of the telescope and the height of the cliff above the ground:
$90.6+1.3=91.9$

We can conclude that the eagle is 91.9 meters above the ground; therefore, the correct answer is <span>B 91.9 m</span>

6 0

3 years ago