Question

an equation that is perpendicular to x-3y=3 and pases through the point (5,-9) in slope-intercept form

Answer 1

Answer:

y = - 3x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

x - 3y = 3 ( subtract x from both sides )

- 3y = - x + 3 ( divide all terms by - 3 )

y = $\frac{1}{3}$ x - 1 ← in slope- intercept form

with slope m = $\frac{1}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{3} }$ = - 3, then

y = - 3x + c ← is the partial equation

To find c substitute (5, - 9) into the partial equation

- 9 = - 15 + c ⇒ c = - 9 + 15 = 6

y = - 3x + 6 ← equation of perpendicular line