an equation that is perpendicular to x-3y=3 and pases through the point (5,-9) in slope-intercept form
1 answer:
Answer:
y = - 3x + 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
x - 3y = 3 ( subtract x from both sides )
- 3y = - x + 3 ( divide all terms by - 3 )
y = x - 1 ← in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= - 3, then
y = - 3x + c ← is the partial equation
To find c substitute (5, - 9) into the partial equation
- 9 = - 15 + c ⇒ c = - 9 + 15 = 6
y = - 3x + 6 ← equation of perpendicular line
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Answer:
392.5 in²
Step-by-step explanation:
This figure is consists of a trapezium and a rectangle.
So, to find the total area of the figure you have to find the area of the trapezium and the rectangle separately and add them together.
Let us find now.
<u>Area of the Trapezium</u>
Area = × ( sum of the parallel sides ) × height
Area = × ( 9 + 20 ) × 5
Area = × 29 × 5
Area = × 145
Area = 72.5 in²
<u>Area of the rectangle</u>
Area = Length × Width
Area = 20 × 16
Area = 320 in²
<u>Total area of the figure</u>
Total area = Area of the trapezium + Area of the rectangle
Total area = 72.5 in² + 320 in²
Total area = 392.5 in²
Hope this helps you :-)
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