an equation that is perpendicular to x-3y=3 and pases through the point (5,-9) in slope-intercept form
1 answer:
Answer:
y = - 3x + 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
x - 3y = 3 ( subtract x from both sides )
- 3y = - x + 3 ( divide all terms by - 3 )
y = x - 1 ← in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= - 3, then
y = - 3x + c ← is the partial equation
To find c substitute (5, - 9) into the partial equation
- 9 = - 15 + c ⇒ c = - 9 + 15 = 6
y = - 3x + 6 ← equation of perpendicular line
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Question is Incomplete, Complete question is given below.
School started at 8:05 a.m and ended at 2:40 p.m. the work below shows Erica's calculation of the length of the school day
Which two errors did Erica make
A.She subtracted instead of adding the times
B.She subtracted the end time from the start time
C.She did not regroup on hours for 60 minutes to subtract the minutes
D.she did not account for a.m. and p.m. in the start and end times.
E.see switch to hours and minutes in both the start and end times
Answer:
B. She subtracted the end time from the start time and
D. She did not account for a.m. and p.m. in the start and end times.
Step-by-step explanation:
The school started at 8:05 a.m. and ended at 2:40 p.m.
And the length of the school day is calculated by Erica and it is shown in the attached photo.
See the attached photo.
Erica has done two errors which are
B. She subtracted the end time from the start time and
D. She did not account for a.m. and p.m. in the start and end times.
