Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
C.) -7x - 5y = -48
Step-by-step explanation:
slope AB = (y2 - y1)/(x2-x1)
= {4-(-1)}/{4-(-3)} = 4+1/4+3 = 5/7
slope of BC = -1 ÷ 5/7 = -1 × 7/5 = -7/5
taking -7x - 5y = -48
-5y = 7x -48
y = 7x/-5 - 48
y = -7/5x -48