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Licemer1 [7]
3 years ago
9

How would you write 0.7 repeated as a fraction

Mathematics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

7/9

Step-by-step explanation:

7/9 = 0.777777777777777777...

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En la meta de aprendizaje<br>En el plan de investigación​
sveta [45]

Answer:

in the goal of learning. in the investigation plan

4 0
3 years ago
Evaluate the piecewise function below for f(1):
lorasvet [3.4K]

We need to find f(1)

f(1) means x=1

Now we look at the three inequalities and choose the one where x=1 satisfies

x<=-1 , -1<x<1  and x>=1

x=1 satisfies the inequality x>=1

so we use the third function to find f(1)

f(x) = 2x^2 + 3

We plug in 1 for x and find f(1)

f(1) = 2(1)^2 + 3= 2 + 3 = 5

f(1) = 5

3 0
3 years ago
A researcher would like to determine whether a new tax on legalized marijuana has had any effect on people’s purchasing behavior
riadik2000 [5.3K]

Answer:

a) z=\frac{386-410}{\frac{60}{\sqrt{9}}}=-1.2    

p_v =2*P(z  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not different from 410 at 5% of signficance.  

b) z=\frac{386-410}{\frac{30}{\sqrt{9}}}=-2.4  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significantly different from 410 at 5% of signficance.  

Step-by-step explanation:

Part a

Data given and notation  

\bar X=386 represent the sample mean    

\sigma=60 represent the population standard deviation

n=9 sample size  

\mu_o =410 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean differs from 410, the system of hypothesis would be:  

Null hypothesis:\mu =410  

Alternative hypothesis:\mu \neq 410  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{386-410}{\frac{60}{\sqrt{9}}}=-1.2  

P-value  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not different from 410 at 5% of signficance.  

Part b

z=\frac{386-410}{\frac{30}{\sqrt{9}}}=-2.4  

P-value  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significantly different from 410 at 5% of signficance.  

6 0
3 years ago
A survey showed that, in one city, 20.7% of the population used
Ne4ueva [31]

Answer:

Step-by-step explanation:

a) 0.5*0.365=18.25%

b) (100%-20,7%-50%)=29.3

5 0
3 years ago
Which statement is true regarding the parallel and
Irina-Kira [14]

Answer:

C

Step-by-step explanation:

because it's C

6 0
3 years ago
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