If P = -4,3 and Q = 2,1 are the endpoints of the diameter of a circle, find the equation of the circle. Help pls :/ 30 points!!
1 answer:
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Answer:
x=1, y=-5
Step-by-step explanation:
Given equations are:
In order to solve the equation
Multiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting them
So,
Eqn 1 becomes
15x+50y=-235
Eqn 2 becomes
15x-21y=120
Subtracting 2 from a
15x+50y - (15x-21y) = -235-120
15x+50y-15x + 21y = -355
71y = -355
y = -355/71
y =-5
Putting y= -5 in eqn 1
3x+10(-5) = -47
3x -50 = -47
3x = -47+50
3x = 3
x = 3/3
x = 1
Hence the solution is:
x=1, y=-5
SIDE LENGTH OF TRIANGLE: 2.14 inches
SIDE LENGTH OF HEXAGON: 6 inches
To solve this problem, we know that the shapes have equal sides as it states “equilateral triangle”. A triangle has 3 sides and a hexagon has 6 sides. We are told the perimeters are the same so you can set their perimeters equal to each other to solve for x. You would get this : 3(1.4x + 2) = 6(0.5x +2)
With basic algebra you would get x= 5
Then you substitute that value into the length sides of the triangle and hexagon. For the triangle you would approx get 2.14 inches and for the hexagon 6 inches
SIDE LENGTH OF HEXAGON: 6 inches
To solve this problem, we know that the shapes have equal sides as it states “equilateral triangle”. A triangle has 3 sides and a hexagon has 6 sides. We are told the perimeters are the same so you can set their perimeters equal to each other to solve for x. You would get this : 3(1.4x + 2) = 6(0.5x +2)
With basic algebra you would get x= 5
Then you substitute that value into the length sides of the triangle and hexagon. For the triangle you would approx get 2.14 inches and for the hexagon 6 inches