<span>x in (-oo:+oo)
3/8-((2/3)*x) = 11/12 // - 11/12
3/8-((2/3)*x)-(11/12) = 0
(-2/3)*x+3/8-11/12 = 0
-2/3*x-13/24 = 0 // + 13/24
-2/3*x = 13/24 // : -2/3
x = 13/24/(-2/3)
x = -13/16
x = -13/16
</span>
Answer:
the Pythagorean formula is a²+b²=c², which is a and b are the x and y distances between points and c is the hypotenuse, which is the distance.
Step-by-step explanation:
First find the length of the diagonal of a square of side 4 inches:
d^2 = 4^2 + 4^2 = 2*4^2 = 32. Then the diagonal of the cube has length
sqrt( 32 + 4^2) = sqrt(32+16) = sqrt(48) = 4sqrt(3).