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babymother [125]
3 years ago
13

What is the length of the diagonal of a cube of 4 inches

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

First find the length of the diagonal of a square of side 4 inches:


d^2 = 4^2 + 4^2 = 2*4^2 = 32. Then the diagonal of the cube has length


sqrt( 32 + 4^2) = sqrt(32+16) = sqrt(48) = 4sqrt(3).

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What is the quotient of (x3 + 6x2 + 11x + 6) ÷ (x2 + 4x + 3)? x + 2 x – 2 x + 10 x + 6
evablogger [386]

Answer:

x + 2

Step-by-step explanation:

If we know one of the factors, we should be able to use long division.

We can divide the trinomial by the binomial and find the other factor.

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                         <u>2x² + 8x + 6</u>

                                           0

Thus,

\dfrac{x^{3} + 6x^2 + 11x + 6} {x^{2} + 4x + 3} = \mathbf{x + 2}

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3 0
3 years ago
Hello can you help meee
VARVARA [1.3K]

Answer:

x=4\sqrt{2}

Step-by-step explanation:

The given triangle is a 45°-45°-90° triangle. Use the following rule:

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h=4*\sqrt{2}

Simplify:

h=4\sqrt{2}

:Done

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