Answer:
set y=0 in one of the equations and then in the other one set x=0
Step-by-step explanation:
below is how you do it
y=5x-5 y=3x+3
0=5x-5 y=3(0) +3
5=5x y=3
1=x
Answer: 2.11cm
Step-by-step explanation:
Given the following :
The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm
The area of trapezoid is calculated using the formula:
1/2(a + b) × h
Where ;
a = Length of side 1
b = length of side 2
h = height
Take a = (2z + 3) and b = (6z – 1), h = z
Therefore ;
1/2 (2z + 3 + 6z - 1) × z
Opening the bracket
(z + 1.5 + 3z - 0.5) × z
(4z + 1 ) × z = 20cm^2
4z^2 + z = 20cm^2
Using Quadratic formula:
4z^2 + z - 20 = 0
a = 4, b = 1, c = - 20
(-b±√b^2 -4ac) / 2a
Z = 2.11 or - 2.364
z cannot be negative, therefore,
Z = 2.11 cm
Answer:
Yes. Bc 8 have a negative sign infront of it so 9 greater
Answer:
y-6=-3/4(x+4)
Step-by-step explanation:
y-y1=m(x-x1)
m=-3/4
y-6=-3/4(x-(-4))
y-6=-3/4(x+4)
Answer:
1. 14 = 2 + 12
2. 16 = 4 + 12
3. 18 = 6 + 12
4. 20 = 8 + 12
Step-by-step explanation:
Super easy. All you do is replace the numbers in your table with the corresponding letter. In this case we have a table of s and f.
Example for row two: f = s + 12. Replace s with 4 ( 4 is from your s column so you would replace it with that) then solve and plug in your answer (When you solve your answer, it will go under f column).16 = 4 + 12 . f = 16, s = 4.
Formula = f = s + 12.
1. 14 = 2 + 12
2. 16 = 4 + 12
3. 18 = 6 + 12
4. 20 = 8 + 12
