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2 years ago

Question 1 (Multiple Choice Worth 1 points)

Mathematics

1 answer:

Oksi-84 [34.3K]2 years ago

4 0

Sorry I don't know but i bet more can exolain.

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3 years ago

Read 2 more answers

Enter the slope-intercept equation of the line that has the same slope as y - 3 = (x + 3) and contains

mario62 [17]

Given:

$y-3=\frac{1}{2}(x+3)$

Point = (8, 4)

To find:

The slope-intercept form of the equation of the line.

Solution:

$$y-3=\frac{1}{2}(x+3)$

Slope of this line = $\frac{1}{2}$ .

Slope of the line is same as the slope of $y-3=\frac{1}{2}(x+3)$ .

Slope of the line (m) = $\frac{1}{2}$

General form of line:

y = mx + b

$y=\frac{1}{2} x+b$ ---------- (1)

It contains the point (8, 4). Substitute x = 8 and y = 4 in (1).

$4=\frac{1}{2}( 8)+b$

$4=4+b$

Subtract 4 from both sides, we get

b = 0

Substitute b = 0 in (1).

Equation of the line:

$y=\frac{1}{2} x+0$

$$y=\frac{1}{2} x$

<u>Complete the sentence:</u>

$y=\frac{1}{2} x$ ; I used the general form of a line in slope-intercept form, y = mx + b. The slope, m is $\frac{1}{2}$ . Then I substituted 8 for x and 4 for y into the standard form and solved for b, which is 0.

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3 years ago