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IRISSAK [1]
2 years ago
5

Question 1 (Multiple Choice Worth 1 points)

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
4 0

Sorry I don't know but i bet more can exolain.

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Enter the slope-intercept equation of the line that has the same slope as y - 3 = (x + 3) and contains
mario62 [17]

Given:

y-3=\frac{1}{2}(x+3)

Point = (8, 4)

To find:

The slope-intercept form of the equation of the line.

Solution:

$y-3=\frac{1}{2}(x+3)

Slope of this line = \frac{1}{2}.

Slope of the line is same as the slope of  y-3=\frac{1}{2}(x+3).

Slope of the line (m) = \frac{1}{2}

General form of line:

y = mx + b

y=\frac{1}{2} x+b ---------- (1)

It contains the point (8, 4). Substitute x = 8 and y = 4 in (1).

4=\frac{1}{2}( 8)+b

4=4+b

Subtract 4 from both sides, we get

b = 0

Substitute b = 0 in (1).

Equation of the line:

y=\frac{1}{2} x+0

$y=\frac{1}{2} x

<u>Complete the sentence:</u>

y=\frac{1}{2} x; I used the general form of a line in slope-intercept form, y = mx + b. The slope, m is \frac{1}{2}. Then I substituted 8 for x and 4 for y into the standard form and solved for b, which is 0.

7 0
3 years ago
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