<span>There are 4 vans. So we have that probability that the first vehicle is a van p (e) = 4/10 = 0.4.
P(e|f) = P( f and e) / p (f)
p(e) = 0.4 and p(f) = 3/9
P (f and e) = 0.40 * 0.33 = 0.132
So p(e|f) = 0.4 * 0.33/ 0.33 = 0.4
P(f and e) p(f) * p(e) = 0.4 * 0.33 = 0.132</span>
Answer:
p(4 successes) ≈ 7.7%
Step-by-step explanation:
p(k successes in n trials) = C(n,k)·p^k·(1-p)^(n-k)
You have n=5, k=4, p=0.4, so the probability is ...
p(4 successes) = C(5,4)·(0.4)^4·(1 -0.4)^1 = 5·0.4^4·0.6 = 0.0768
p(4 successes) ≈ 7.7%
Answer:
120
Step-by-step explanation:
We are given that the function for the number of students enrolled in a new course is
.
It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.
We know that the average rate of change is given by,
,
where f(x)-f(a) is the change in the function as the input value (x-a) changes.
Now, the number of students enrolled at 4 = f(4) =
= 255 and the number of students enrolled at 2 = f(2) =
= 15
So, the average increase
=
=
= 120.
Hence, the average increase in the number of students enrolled is 120.
Answer:
no I can't u just ruined my mood
Step-by-step explanation:
green: 6/4
red: 7/4
this is all i know