U say the answer is D 7$......
AB is 6 because you just subtract BC from AC to find the other missing length.
Answer:
Step-by-step explanation:
a-number of advance tickets
s-number of same day tickets
a*40+s*25=2400
a +s =75
I solve with the substitution method
s=75-a
40a+25*(75-a)=2400
40a+1875-25a=2400
15a=2400-1875
15a=525
a=525/15
a=35
so s=75-35
s=40
5(n-4)=(4n-12)
First: Distribute 5 into n and -4.
5(n-4)=(5n)+(5*-4)= 5n-20.
Second: Subtract 4n from both sides to eliminate the variable from the right side of the equation.
(5n-20)=(4n-12)
n-20=-12
Next: Add 20 to both sides to eliminate the constant from the left side of the equation.
n-20=-12
n=8
The unknown number is 8.
Part b is 64 i think
hope this helps:))
