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pantera1 [17]
2 years ago
14

Find the area of triangle ABC Remember, the distance between two points is

2%7D%20-x_%7B1%7D%20%29%2B%28y_%7B2%7D%20-y_%7B1%7D%20%29%5E%7B2%7D" id="TexFormula1" title="d=\sqrt(x_{2} -x_{1} )+(y_{2} -y_{1} )^{2}" alt="d=\sqrt(x_{2} -x_{1} )+(y_{2} -y_{1} )^{2}" align="absmiddle" class="latex-formula"> Round the answer to the nearest tenth.
A.
3.8 square units
B.
9.5 square units
C.
108.7 square units
D.
109.9 square units
Mathematics
1 answer:
MakcuM [25]2 years ago
5 0

Answer:

B. 9.5 square units

Step-by-step explanation:

right on edge 2022

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A(-3,-2) what is the answer
bagirrra123 [75]

Answer:

X=3 and X=2 eassyyyy

Step-by-step explanation:

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4 0
3 years ago
Find the x-intercept and the y-intercept of the graph of the equation 1/3x + 9y = 15. Then graph the equation.
AleksAgata [21]

Answer: the x intercept is (45,0) and the y intercept is (0,5/3)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use substitution to solve the following system of equations. Show all of your work. Write the solution as an ordered pair.
trapecia [35]

Answer:

\left \{ {{x=2} \atop {y=2}} \right.

Step-by-step explanation:

Substitute the second equation into the first one:

4x+(2x-2)=10\\6x-2=10\\6x=12\\x=2

Substitute x=2 into the second equation:

y=2\times 2-2\\y=4-2\\y=2

\therefore \left \{ {{x=2} \atop {y=2}} \right.

3 0
2 years ago
6. All angles in the figure below are right angles. What is the area of the figure? (1 point)
lilavasa [31]

Answer:

Option (4)

Step-by-step explanation:

Area of the figure given in the picture = Area of large rectangle - Area of rectangle A

Area of rectangle A = Length × Width

                                 = [9 - (2 + 4)] × 3

                                 = 3 × 3

                                 = 9

Area of the large rectangle = Length × Width

                                             = 9 × 5

                                             = 45

Therefore, area of the given figure = 45 - 9

                                                          = 36

Option (4) will be the correct option.

5 0
3 years ago
An object with a starting velocity of 15 m/s accelerates at 3 m/s2. How far does the object travel within 10 seconds?
Anna007 [38]

Answer:  300 m

<u>Step-by-step explanation:</u>

distance(s)=v_it+\dfrac{1}{2}at^2 \quad \text{where}\ v_i \text{is initial velocity, a is acceleration, t is time}

s=(15)(10)+\dfrac{1}{2}(3)(10)^2

  = 150 + 150

  = 300

6 0
3 years ago
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