The y intercept is the point at which the line crosses the y axis. In order to find this point x must be 0. To solve this problem, start by plugging in 0 for x. You should get -22y = 88. Then divide both sides by -22. Your final answer should be y=-4
Answer:
1750
Step-by-step explanation:
well first you need to know that 100 percent from yesterday is 1400, so you now want to know what 125 percent of that is. 100 x 14 is 1400 right, so 125 x 14 is 1750.
hope this helps
Answer:
16p
Direction: positive/upward direction
Step-by-step explanation:
First, the function is f(x,y) = 4ypx
At the point where x=4 and y=1, the maximum rate of change of the function f(x,y) is
4(1)p(4) = 16p
The direction in which it occurs is the positive(upward) direction
Answer:
![EF = 13](https://tex.z-dn.net/?f=EF%20%3D%2013)
![GH = 5](https://tex.z-dn.net/?f=GH%20%3D%205)
![EH = 13](https://tex.z-dn.net/?f=EH%20%3D%2013)
Step-by-step explanation:
Given
The attached figure
![EG = 12](https://tex.z-dn.net/?f=EG%20%3D%2012)
![FG = 5](https://tex.z-dn.net/?f=FG%20%3D%205)
Solving (a): EF
Since m is a perpendicular bisector, then <EGF and <EGH are right-angled.
So, EF will be calculated using Pythagoras theorem which states:
![EF^2 = EG^2 + FG^2](https://tex.z-dn.net/?f=EF%5E2%20%3D%20EG%5E2%20%2B%20FG%5E2)
![EF^2 = 12^2 + 5^2](https://tex.z-dn.net/?f=EF%5E2%20%3D%2012%5E2%20%2B%205%5E2)
![EF^2 = 144 + 25](https://tex.z-dn.net/?f=EF%5E2%20%3D%20144%20%2B%2025)
![EF^2 = 169](https://tex.z-dn.net/?f=EF%5E2%20%3D%20169)
Take the positive square roots of both sides
![EF = \sqrt{169](https://tex.z-dn.net/?f=EF%20%3D%20%5Csqrt%7B169)
![EF = 13](https://tex.z-dn.net/?f=EF%20%3D%2013)
Solving (b): GH
Since m is a perpendicular bisector, then GH = FG
![FG = 5](https://tex.z-dn.net/?f=FG%20%3D%205)
![GH = FG](https://tex.z-dn.net/?f=GH%20%3D%20FG)
![GH = 5](https://tex.z-dn.net/?f=GH%20%3D%205)
Solving (c): EH
Since m is a perpendicular bisector, then EH = EF
![EF = 13](https://tex.z-dn.net/?f=EF%20%3D%2013)
![EH = EF](https://tex.z-dn.net/?f=EH%20%3D%20EF)
![EH = 13](https://tex.z-dn.net/?f=EH%20%3D%2013)