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Ber [7]
3 years ago
14

I need help please?!!!!

Mathematics
1 answer:
Marianna [84]3 years ago
6 0
The answer is the last option: The associative property of multiplication
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Nine pieces of 8 in. ✕ 12 in. duct that is 2 2 3 ft in length is needed for a building. What is the total length (in ft) needed?
kodGreya [7K]

This question is incomplete, the complete question is;

Nine pieces of 8-in. × 12-in. duct that is 2\frac{2}{3} ft in length is needed for a building. What is the total length (in ft) needed?

Answer:

the total length needed is 24 ft

Step-by-step explanation:  

Given the data in the question;

the length of one piece of 8-in. × 12-in. duct is 2\frac{2}{3} ft

Now to find the total length for nine pieces of the duct;

we simple multiply 2\frac{2}{3} ft  by nine

so

Total length = 9 × 2\frac{2}{3}  

we convert the mixed fraction to improper fraction

2\frac{2}{3}  = 8/3

so

Total length = 9 × (8/3) ft

Total length = 24 ft

Therefore, the total length needed is 24 ft

8 0
3 years ago
What is the value of x in the following equation: 2=x+5 ?
natali 33 [55]
Im pretty sure the value of x in this equation is -3 because -3 plus 5 would equal 2.
6 0
3 years ago
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Explain how you can round 25.691 to the greatest place.
labwork [276]
If it is to the tenth, then you have to look at the hundredth place, if the number in the hundredth place is over 5 or 5, then you have to make the number in the tenth place move up one digit if it isn't over 5 or 5, then you don't do anything
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◆ Quadratic Equations ◆<br>Please help !
Mila [183]
I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

\sf ax^2+(1-a(b+c))x+abc-d)

\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))

Simplify into standard form:

\sf x^2+(1-1(5))x+6-4

\sf x^2+(1-5)x+2

\sf x^2-4x+2

Use the quadratic formula to solve:

\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

For functions in the form of \sf ax^2+bx+c. So in this case:

a = 1
b = -4
c = 2

Plug them in:

\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}

Solve for 'x':

\sf x=\dfrac{4\pm\sqrt{16-8}}{2}

\sf x=\dfrac{4\pm\sqrt{8}}{2}

\sf x\approx\dfrac{4\pm 2.83}{2}

\sf x\approx 0.59,3.41

So the answer would be A.
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PIC IS THE QUESTION AND ANSWERS
Yanka [14]
4/5 and 40/50 are both equivalent
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