crosses x-axis at (2, 0 ) and y-axis at (0, - 4 )
To find where the graph crosses the x and y axes ( intercepts )
• let x = 0, in the equation for y- intercept
• let y = 0, in the equation for x- intercept
x = 0 : y = 0 - 4 = - 4 ⇒ (0, - 4 )
y = 0 : 2x - 4 = 0 ⇒ 2x = 4 ⇒ x = 2 ⇒ (2, 0 )
The location of the vertex tells you the horizontal and vertical shift. (The parent function f(x) = x² has its vertex at the origin, (0, 0). The vertical distance of the point 1 unit left or right of the vertex in relation to the vertex tells you the vertical scale factor (stretch).
g(x) = f(x +3) -3
horizontal shift left 3
vertical shift down 3
h(x) = -3f(x)
reflection across the x-axis
vertical stretch of 3
d(x) = f(x -3) -3
horizontal shift right 3
vertical shift down 3
Answer:
Multiplication is basically repeating addition
Step-by-step explanation:
So, on a numberline, start at 0 then add -6 three times (since you are multiplying it by three) and you should get -18
Write out the expression 2 - (2x-7)^2. That's it.
But if you want to go further and remove the parentheses, first expand (2x-7)^2: (2x-7)^2 = 4x^2 - 28x + 49,
and then subtract this result from 2:
2 - (4x^2 - 28x + 49) (It's important to use parentheses here)
Now, following the distributive property of multiplication, remove the parentheses:
2 - 4x^2 + 28x - 49
Combining the constants, we get the final answer: - 4x^2 + 28x - 47
