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3 years ago

Can someone help me I don’t know how to do this it’s hard and confusing me

Mathematics

1 answer:

Svetach [21]3 years ago

4 0

9514 1404 393

Answer:

increasing on 0 < x < 2
f(2) = 4
decreasing on 2 < x < 5

Step-by-step explanation:

You need to know that an even function is symmetrical about the y-axis. The graph to the right of the y-axis is the mirror image of the graph to the left. With that in mind, the questions are easily answered.

It might help to draw the function graph, as we did in the attached. Then it is more straightforward to see what is happening in each of the intervals.

The function is increasing in the interval 0 < x < 2.

The function value at x=2 is 4: f(2) = 4.

The function is decreasing in the interval 2 < x < 5.

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-40-8b=-6(1+7b) what’s the answer

Andre45 [30]

$\text{Hey there!}$

$\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}$

$\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}$

$\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}$

$\mathsf{ADD\ by\ 42b\ on\ your\ sides}\\\mathsf{-8b-40+42b=-42b-6+42b}\\\mathsf{SOLVE\ above\ correct\ to\ get\ us\ to\ the\ next\ step!}\\\mathsf{\rightarrow 34b-40=-6}$

$\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}$

$\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}$

$\boxed{\boxed{\boxed{\boxed{\mathsf{Thus\ your\ answer\ is:\boxed{\boxed{\mathsf{b=1}}}}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

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3 years ago

You rotate a triangle 90° counterclockwise about the origin. Then you translate its image 1 unit left and 2 units down. The vert

sergiy2304 [10]

Answer:

The coordinates of the original triangle are (2,4). (4,1) and (1,1)

Step-by-step explanation:

About the origin, I have to rotate a triangle 90° counterclockwise. Then I translate its image 1 unit left and 2 units down.

The vertices of the final image are (-5,0), (-2,2), and (-2,-1).

We need to get the vertices of the original triangle.

So, start from a triangle with vertices (-5,0), (-2,2), and (-2,-1) and do the reverse to get the original triangle.

So, we will translate the image triangle by 1 unit right and 2 units up and we will get the triangle with vertices (-5 + 1, 0 + 2), (- 2 + 1, 2 + 2) and (- 2 +1, - 1 + 2) ≡ (-4,2), (-1, 4) and (-1,1).

Now, we have to rotate this intermediate triangle by 90° clockwise.

Therefore, the coordinates of the original triangle are (2,4). (4,1) and (1,1) (Answer)

{Since, for 90° rotation the coordinates of all the vertices will interchange their location (i.e. x-value to y-value and y-value to x-value) and a negative sign will be added to the y-coordinate of the interchanged coordinates}

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3 years ago

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Jobisdone [24]

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